The first five positive integer terms for 3n + 4 are: 1 = 7 2 = 10 3 = 13 4 = 16 5 = 19
100-3(1) = 100-3 = 97 100-3(2) = 100-6 = 94 100-3(3) = 100-9 = 91 Over here N is the first 3 terms, 1, 2, and 3.
3,6,9,12.....
3n + 14 = 83n = 8 - 14 = -63n/3 = -6/3n = -2The value of n is -2.
First you add 4 and 3 then you get 7 so you write the problem like this 3n + 7 and that is your answer
3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (4) = 3n + 6
3n+2 + (3n+3 - 3n+1) = 3n+1+1 + (3n+1+2 - 3n+1) = 3*3n+1 + (9*3n+1 - 3n+1)= (3+9-1)*3n+1 = 11*3n+1.
Simplify -6n+2+3n-3 So first let's combine the n terms. -6n and 3n is -3n since -6 and 3 is -3. Or, think of being in debt 6 dollars as -6n and someone gives you 3 dollars just because they are nice like those people who answer WikiAnswers.com. Now you are only in debt 3 dollars which we denote as -3 and n could be dollars or cents. Bottom line, when you combine the n's it is -3n. Next combine the numbers or constant terms, 2-3 is the same as 2+ (-3) which is -1. So the answer is -3n-1 which can also be written as -(3n+1)
8
n = 1 ---> 3 * 1 + 3 = 6 n = 2 ---> 3 * 2 + 3 = 9 first 2 have difference of 3, so you can keep adding 3 to find more terms. 6, 9, 12, 15
Yes when multiplying. No when adding. 3n^3 + 3n^3 = 6n^3 3n^3 x 3n^3 = 9n^6
3 + 3n = 9 + 2n + 4n n = -2
The first five positive integer terms for 3n + 4 are: 1 = 7 2 = 10 3 = 13 4 = 16 5 = 19
100-3(1) = 100-3 = 97 100-3(2) = 100-6 = 94 100-3(3) = 100-9 = 91 Over here N is the first 3 terms, 1, 2, and 3.
3n + 9 = 3(n + 3)
3n + 4 = 7(- 4 from both sides)3n = 3(divide both sides by 3)n = 1
3n+1=7 3*2+1=7