With the equation of an ellipse in the form (x/a)² + (y/b)² = 1 the axes of the ellipse lie on the x and y axes and the foci are √(a² - b²) along the x axis.
9x² + 25y² + 100y - 125 = 0
→ (3x)² + 25(y² + 4y + 4 - 4) = 125
→ (3x)² +25(y + 2)² - 100 = 125
→ (3x)² +25(y + 2)² = 225
→ (3x)²/225 + (y + 2)²/9 = 1
→ (x/5)² + ((y+2)/3)² = 1
Thus the foci are √(5² - 3²) = √16 = 4 either side of the y-axis, but the y axis has been shifted up by 2, thus the two foci are (-4, -2) and (4, -2).
It is the Cartesian equation of an ellipse.
104
2 squared plus 2 x 3 = 10, 7 squared plus 7 x 2 = 63, 6 squared plus 6 x 5 = 66,8 squared plus 8 x 4 = 96 so 9 squared plus 9 x 7 = 81 + 63 = 144.
you use A squared plus B squared equals C squared
To calculate 6 squared plus 8 squared, you first need to square each number individually. 6 squared is 6 x 6, which equals 36. 8 squared is 8 x 8, which equals 64. Adding these two results together, you get 36 + 64, which equals 100. So, 6 squared plus 8 squared is 100.
It is the Cartesian equation of an ellipse.
x = ±2
This is not possible, since the point (4,6) lies inside the circle : X2 + Y2 = 16 Tangents to a circle or ellipse never pass through the circle
104
89
pythagoras
6 squared is 36, and 8 squared is 64. Adding these together, 36 + 64 equals 100. Therefore, 6 squared plus 8 squared equals 100.
2 squared plus 2 x 3 = 10, 7 squared plus 7 x 2 = 63, 6 squared plus 6 x 5 = 66,8 squared plus 8 x 4 = 96 so 9 squared plus 9 x 7 = 81 + 63 = 144.
b = 14324.80366
8^*2) + b^(2) = 18^(2) Algebraically rearranger b^(2) = 18^(2) - 8^(2) Remember two squared terms with a negative (-) between them factors to b^(2) = (18 - 8)( 18 + 8) b^(2) = 10( 26) b^(2) = 260 b = +/- sqrt(260) b = +/- 16.124....
X = √63
This is the common form of the Pythagorean Theorem. It describes the relationship between the two legs of a right triangle and the hypotenuse.