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What is the sum of angles in a 28-sided polygon?
The sum of the interior angles of a polygon with n sides is 180o × (n - 2), consequently the sum of the interior angles of a 28-sided polygon is 4680o (180o × 26).
What is the sum of the interior angles of a 28-gon?
For an n-sided regular polygon, the sum of the interior angles is equal to 180 x (n - 2). In the case of a 28-sided polygon, this would be 180 x (28 - 2) = 180 x 26 = 4680 degrees.
What is the sum of the angle measures in a 26 gon?
The sum of the interior angles of any n-sided polygon is (2n - 4) right angles. Your example has n = 26 so total is (52 - 4) x 90 degrees, ie 48 x 90 which is4320 degrees.
What is the measure if each interior angle of a regular polygon with 15 sides?
Two ways to calculate the required angle. 1) Use the formula S = 2n - 4 right angles S is the sum of the interior angles of a polygon, n is the number of sides. Then, S = (2 x 15) - 4 = 26 right angles = 26 x 90 = 2340° So, each interior angle of a regular 15-sided polygon measures 2340/15 = 156° 2) Calculate the exterior angle and subtract from 180° to obtain the interior angle. Sum of exterior angles = 360° Each exterior angle measures, 360/15 = 24° Each interior angle measures, 180 - 24 = 156°
How many sides does my polygon have if the sum of the interior angles add up too 4320?
There are (4320+360)/180 = 26 sides
