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Suppose width is x metres. Then length is x+5 metres.

Now, perimeter = 2*(width + length)

so 54 = 2*[x + (x+5)] = 2*(2x + 5)

So 27 = 2x + 5 => 22 = 2x => x = 11 and so x+5 = 16.

So the length and width are 16 and 11 metres, respectively.

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Q: What are the length and width of a rectangle with a perimeter of 54 meters if the length of the rectangle is 5 meters longer than the width?
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