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Suppose width is x metres. Then length is x+5 metres.

Now, perimeter = 2*(width + length)

so 54 = 2*[x + (x+5)] = 2*(2x + 5)

So 27 = 2x + 5 => 22 = 2x => x = 11 and so x+5 = 16.

So the length and width are 16 and 11 metres, respectively.

Q: What are the length and width of a rectangle with a perimeter of 54 meters if the length of the rectangle is 5 meters longer than the width?

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Perimeter of rectangle = 2 x (length + width) = 2 x (1.6 + 0.8) = 2 x 2.4 = 4.8 meters

To find the perimeter of the rectangle you add up all the sides. There are two lengths and widths for every rectangle, so you know the length is 40 meters x 2 = 80 meters. Perimeter is the total length of all the sides so you just minus 120 from the two lengths which is 80. So the width is 40, divide 2 (2 widths) = 20 meters. Width = 20 meters OR if they're asking for widthS then it'll be 40 meters, but they're not.

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The perimeter of a rectangle is 42. Meters. The length of the rectangle is threemeter less than twice the width.Mar

Perimeter of rectangle = 2 x (length + width) = 2 x (1.6 + 0.8) = 2 x 2.4 = 4.8 meters

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Perimeter of a rectangle = twice (length + width), in this case 22 m.

The perimeter is 42 metres.

24 meters

because

The perimeter of a rectangle is given by:P = 2l + 2w, where P is the perimeter of the rectangle, l is the length of the rectangle, and w is the width of the rectangle.P = 2(15) + 2(10) = 50 meters.

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A 6 by 4 rectangle will have a perimeter of 20 units

The width of the rectangle is 13 meters. The perimeter of the rectangle is 50 meters, and its length is 12 meters. The 50 meters is 2 times the length plus 2 times the width. With a length of 12 meters, twice that is 24 meters. That leaves 50 meters - 24 meters for twice the width. And 50 - 24 = 26, which is twice the width. The 26 meters divided by 2 = 13 meters, which is the width of the rectangle.

5 meters