Suppose width is x metres. Then length is x+5 metres.
Now, perimeter = 2*(width + length)
so 54 = 2*[x + (x+5)] = 2*(2x + 5)
So 27 = 2x + 5 => 22 = 2x => x = 11 and so x+5 = 16.
So the length and width are 16 and 11 metres, respectively.
Perimeter of rectangle = 2 x (length + width) = 2 x (1.6 + 0.8) = 2 x 2.4 = 4.8 meters
To find the perimeter of the rectangle you add up all the sides. There are two lengths and widths for every rectangle, so you know the length is 40 meters x 2 = 80 meters. Perimeter is the total length of all the sides so you just minus 120 from the two lengths which is 80. So the width is 40, divide 2 (2 widths) = 20 meters. Width = 20 meters OR if they're asking for widthS then it'll be 40 meters, but they're not.
40 meters.
The perimeter of a square is 400 meters. write an equation for the perimeter and solve for the length of one side
26 meters The perimeter (distance around the outside) = length + width + length + width P = 2L + 2W 2 (7) + 2 (6) = 26
The perimeter of a rectangle is 42. Meters. The length of the rectangle is threemeter less than twice the width.Mar
Perimeter of rectangle = 2 x (length + width) = 2 x (1.6 + 0.8) = 2 x 2.4 = 4.8 meters
6 meters
Perimeter of a rectangle = twice (length + width), in this case 22 m.
The perimeter is 42 metres.
24 meters
because
12 meters
The perimeter of a rectangle is given by:P = 2l + 2w, where P is the perimeter of the rectangle, l is the length of the rectangle, and w is the width of the rectangle.P = 2(15) + 2(10) = 50 meters.
A 6 by 4 rectangle will have a perimeter of 20 units
The width of the rectangle is 13 meters. The perimeter of the rectangle is 50 meters, and its length is 12 meters. The 50 meters is 2 times the length plus 2 times the width. With a length of 12 meters, twice that is 24 meters. That leaves 50 meters - 24 meters for twice the width. And 50 - 24 = 26, which is twice the width. The 26 meters divided by 2 = 13 meters, which is the width of the rectangle.
5 meters