1000 ÷ 7 = 142 remainder 6 So, there are 142 numbers between 1 and 1000 that are evenly divisible by 7. 1 x 7 = 7 2 x 7 = 14 3 x 7 = 21 ... 142 x 7 = 994
343!
Oh, what a lovely question! Let's see, we can find the numbers divisible by 3 first, which are 33 numbers, and the numbers divisible by 7, which are 14 numbers. But wait, some numbers are divisible by both 3 and 7, so we must be careful not to count them twice. In the end, there are 47 numbers between 1 and 100 that are divisible by 3 or 7. Happy counting!
343 is divisible by 1, 7, 49, 343.
Just 7. Any other number divisible by 7 isn't prime.
142 of them.
There are 95 numbers in the range of 1 to 1,000 that are divisible by seven but not by three.
1000 ÷ 7 = 142 remainder 6 So, there are 142 numbers between 1 and 1000 that are evenly divisible by 7. 1 x 7 = 7 2 x 7 = 14 3 x 7 = 21 ... 142 x 7 = 994
142
343!
7
142 of them.
There are 14 numbers between 1 & 100 that are divisible by 7.
One of every three numbers is divisible by three. Therefore, 1000/3 (rounded down) tells you how many numbers in that range are divisible by 3. Similar for the number 7. Now, if you add the two, you'll be counting all the multiples of 21 (which is 3 x 7) double. Therefore, you must calculate 1000 / 21 (rounded down), and subtract that from the previous result.
Oh, dude, let me break it down for you. So, first, you find how many numbers are divisible by 6, which is 166. Then you find how many are divisible by 21, which is 47. But wait, don't forget to subtract the ones divisible by both 6 and 21, which is 7. So, the total is 166 + 47 - 7 = 206 integers that fit the bill. Easy peasy!
858
Oh, what a lovely question! Let's see, we can find the numbers divisible by 3 first, which are 33 numbers, and the numbers divisible by 7, which are 14 numbers. But wait, some numbers are divisible by both 3 and 7, so we must be careful not to count them twice. In the end, there are 47 numbers between 1 and 100 that are divisible by 3 or 7. Happy counting!