In 2 rolls, it's 1/6 = 162/3% if you don't care what the number is.
If you name the number you want before rolling, it's 1/36 = 27/9%.
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The probability of rolling the same number on five dice is (1/6)4, or about 0.0007716.
The first roll doesn't matter for probability, it just sets the number to be rolled by the other two. So: P(rolling the same number three times) = P(rolling a particular number)2 = (1/6)2 = 1/36
The probability is 0.0198. The probability of that happening twice is 0.000393 Is this the odds of it happening twice with the same number?
The first number doesn't matter, just that the last three are the same as the first. P(rolling the same as the number before) = 1/6 P(rolling the same number as the first three times = (1/6)3 = 1/216
Gary's chances of rolling either a 4 or a 6 are the same for any of the other numbers on the cube. The probability is 1 out of 3.