300 x 40 = 12000
300 x 8 = 2400
50 x 40 = 2000
50 x 8 = 400
7 x 40 = 280
7 x 8 = 56
Single digits don't have partial products. 8 x 6 = 48
how to find the partial products of a number
the partial products is 2,480 and 310
700 and 210 are the answers to partial products of 77 times 30
A single number, such as 4228, cannot have partial fractions.
To find the partial products for the multiplication of 357 and 48, you can break down the numbers. For instance, you can express 48 as 40 + 8. Then, multiply 357 by each part: (357 \times 40 = 14,280) and (357 \times 8 = 2,856). The partial products are 14,280 and 2,856.
32 and 160
Single digits don't have partial products. 8 x 6 = 48
They are 2000, 400, 280 and 56.
The partial products for 57 times 48 are: 48 multiplied by 7, which equals 336 48 multiplied by 50, which equals 2,400 Adding these two partial products together gives a total product of 2,736.
To find the partial products of 48 times 28, we can break down the numbers. We can express 48 as 40 + 8 and 28 as 20 + 8. Then, we calculate the partial products: 40 × 20 = 800 40 × 8 = 320 8 × 20 = 160 8 × 8 = 64 Adding these together gives 800 + 320 + 160 + 64 = 1344. Thus, the product of 48 and 28 is 1344.
how to find the partial products of a number
The partial-products method is a multiplication strategy that involves breaking down each number into its place value components and multiplying them separately. To find the product of 46 and 98 using the partial-products method, you would multiply each digit of the first number (46) by each digit of the second number (98) and then add the results. For example, 40 x 90 = 3600, 40 x 8 = 320, 6 x 90 = 540, and 6 x 8 = 48. Adding these partial products together gives you the final answer of 3600 + 320 + 540 + 48 = 4508.
5630 is a single number and single numbers do not have partial products.
the partial products for 12 and 3 30 and 6 :)
26
the partial products is 2,480 and 310