Let's call the numbers A and B, A being the bigger number.
So, A - B = 3 and A + B =47
That makes, (A - B) + (A + B) = 2A = 50
Thus, A = 25 and B = 22.
50
23
The sum of the first 500 odd counting numbers is 250,000.
The sum of the first 50 counting numbers, excluding zero, is 1,251.
The sum of the first 10 counting numbers (1-10) is 51.
It is 155 greater.
4990
Yes, the sum of any three consecutive counting numbers has a factor of 3.
24 + 25 + 26 = 75
The sum of the first 500 odd counting numbers is 250,000.
The sum of the first 50 counting numbers, excluding zero, is 1,251.
I assume you mean the first three "counting" (ordinal) numbers, which are 1, 2, and 3. The sum is therefore 1 + 4 + 9 = 14.
The sum of the first six counting numbers (1-6) is 19.
The sum of the first 10 counting numbers (1-10) is 51.
1,2,3,4 1+2+3+4=10 4 times 3 times 2 times 1 =24 24 counting numbers
It is 155 greater.
The sum of the numbers from 1 to 20 inclusive is 220.
The sum of the first 100 counting numbers (1-100) is 5,001.
4990