It depends on what number you would like. Given any real number, it is possible to find a real polynomial of degree 5 that will go through these 5 and the nominated 6th number.
Fitting a polynomial of degree 4 to these numbers, the fitted next number is 44.
Un = (-5n4 + 58n3 - 232n2 + 371n - 186)/6 for n = 1, 2, 3, ...
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All the above is true but just in case the simple answer is the real answer, I'd bet on 4 (then -2, 5,-3)
The number 0 and the next is 2.
4
The next whole number after 1 is 2. However, the decimal after 1 can be an infinite chain of 0's, with a 1 at the end.
This series is of the function f(x) = x2+1, starting with x=0.The next number in the series is 26. The number after that is 37.
The next number is 4, followed by -2
The next term is -2.
The number 0 and the next is 2.
1, 2, 0, 3, -1, 4, -2, 5, -3, 6
4
312 211 110 3-1=2 2-1=1 1-1=0
The next whole number after 1 is 2. However, the decimal after 1 can be an infinite chain of 0's, with a 1 at the end.
16' then 25 and then 36 et.seq. The clue is 0,1,4,9,16,25,36, ... = 0^(2) , 1(2) , 2^(2), 3^(2) , 4^(2) , 5^(2) , 6^(2), ... n^(2) ...
This series is of the function f(x) = x2+1, starting with x=0.The next number in the series is 26. The number after that is 37.
The next number is 4, followed by -2
It is: 0 1 2 3 ... etc
4.
It could be 34, if you use the position to value rule Un = (-9n4 + 106n3 - 429n2 + 692n - 348)/12 for n = 1, 2, 3, ...