It depends on what number you would like. Given any real number, it is possible to find a real polynomial of degree 5 that will go through these 5 and the nominated 6th number.
Fitting a polynomial of degree 4 to these numbers, the fitted next number is 44.
Un = (-5n4 + 58n3 - 232n2 + 371n - 186)/6 for n = 1, 2, 3, ...
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All the above is true but just in case the simple answer is the real answer, I'd bet on 4 (then -2, 5,-3)
The number 0 and the next is 2.
4
The next whole number after 1 is 2. However, the decimal after 1 can be an infinite chain of 0's, with a 1 at the end.
This series is of the function f(x) = x2+1, starting with x=0.The next number in the series is 26. The number after that is 37.
The next number is 4, followed by -2
The next term is -2.
The number 0 and the next is 2.
4
312 211 110 3-1=2 2-1=1 1-1=0
The next whole number after 1 is 2. However, the decimal after 1 can be an infinite chain of 0's, with a 1 at the end.
16' then 25 and then 36 et.seq. The clue is 0,1,4,9,16,25,36, ... = 0^(2) , 1(2) , 2^(2), 3^(2) , 4^(2) , 5^(2) , 6^(2), ... n^(2) ...
This series is of the function f(x) = x2+1, starting with x=0.The next number in the series is 26. The number after that is 37.
The next number is 4, followed by -2
The series appears to be alternating between adding and subtracting numbers. The pattern seems to be adding 1, then subtracting 2, then adding 3, and finally subtracting 4. Following this pattern, the next number in the series would be 1 (subtracting 4 from -1).
It is: 0 1 2 3 ... etc
4.
5.