223455423122343
1113213211
331131211131221
The next number in this sequence is 13112221.
312211 13112221
Is the fourth term correct? Should it not be 111221? Then the next term would be 13112221
1113213211
331131211131221
1113213211
1(one 1) 11(two ones) 21(one two and 1 1 ) and so on so 1 11 21 1211 111221 312211 13112221 1113213211
The next number in this sequence is 13112221.
in start there is one 1 so = 11 11 have 2 one's so = 21 1211 have 1 one 1 two and 2 one's so the next is = 111221 and so on. and your answer is 3113112211121312211312113211
312211 13112221
Is the fourth term correct? Should it not be 111221? Then the next term would be 13112221
The next number in the sequence is 13112221. This sequence is known as the "look-and-say" sequence, where each term is generated by describing the count of consecutive digits in the previous term. For example, "312211" is read as "one 3, one 1, two 2s, and two 1s," which gives rise to "13112221."
The sequence is known as the "look-and-say" sequence. Each term describes the previous term by counting the number of digits in groups. Following this pattern, the next row after 13112221 is 1113213211, which describes one 1, one 3, two 1s, one 2, and two 2s.
The pattern you see is generated by a sequence known as the "look-and-say" sequence. Each term is constructed by describing the digits of the previous term: for example, "1" is described as "one 1" (11), "11" as "two 1s" (21), and so on. This continues, where each term counts and describes the quantities of consecutive identical digits in the previous term.
312211