331131211131221
223455423122343
1113213211
312211 13112221
The next number in this sequence is 13112221.
Is the fourth term correct? Should it not be 111221? Then the next term would be 13112221
223455423122343
1113213211
in start there is one 1 so = 11 11 have 2 one's so = 21 1211 have 1 one 1 two and 2 one's so the next is = 111221 and so on. and your answer is 3113112211121312211312113211
1113213211
1(one 1) 11(two ones) 21(one two and 1 1 ) and so on so 1 11 21 1211 111221 312211 13112221 1113213211
312211 13112221
The next number in this sequence is 13112221.
The last number consists of one 3 followed by one 1 followed by two 2s followed by two 1s Stringing all these numbers together gives 13112221
13211221 111312212211 31131211131221 13211311123113112211 11121221133112132113212221 3112112221232112111312211312113211 1321122132111213122112311311222113111221131221 31131122112231131112132112311321322112111312211312111322212311322113212221
This is a word puzzle describing the digits in the sequence. Literally say what you see to find the next term. 1 = one one 11 = two ones 21 = one two, one one 1211 = one one, one two, two ones... etc . . . So to find the next term: 13112221 = one one, one three, two ones, three twos, one one which is: 1113213211
13112221 1 time 3, 1 time 1, 2 times 2, 2 times 1. and the next would be 1 time 1, 1 time 3, 2 times 1, 3 times 2, 1 time 1 1113213211 and so on.
Is the fourth term correct? Should it not be 111221? Then the next term would be 13112221