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p = q

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Q: What do you know to be true about the values of p and q?
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What type of operator can be used to determine whether a specific relationship that exists between two values?

The relational operators: ==, !=, =.p == q; // evaluates true if the value of p and q are equal, false otherwise.p != q; // evaluates true of the value of p and q are not equal, false otherwise.p < q; // evaluates true if the value of p is less than q, false otherwise.p q; // evaluates true if the value of p is greater than q, false otherwise.p >= q; // evaluates true of the value of p is greater than or equal to q, false otherwiseNote that all of these expressions can be expressed logically in terms of the less than operator alone:p == q is the same as NOT (p < q) AND NOT (q < p)p != q is the same as (p < q) OR (q < p)p < q is the same as p < q (obviously)p q is the same as (q < p)p >= q is the same as NOT (p < q)


What is the truth table for p arrow q?

Not sure I can do a table here but: P True, Q True then P -&gt; Q True P True, Q False then P -&gt; Q False P False, Q True then P -&gt; Q True P False, Q False then P -&gt; Q True It is the same as not(P) OR Q


What do you know about the values of p and q?

Nothing at all! It depends on the context.


Where p and q are statements p and q is called what of p and q?

The truth values.


If p q and q r what is the relationship between the values p and r?

Ifp < q and q < r, what is the relationship between the values p and r? ________________p


If P is true and Q is false what is the truth value of P or Q?

If p is true and q is false, p or q would be true. I had a hard time with this too but truth tables help. When using P V Q aka p or q, all you need is for one of the answers to be true. Since p is true P V Q would also be true:)


What is a comparative operator?

Comparative operators are used to compare the logical value of one object with another and thus establish the rank (ordering) of those objects. There are six comparative operators in total: p&lt;q : evaluates true when p is less than q p&gt;q : evaluates true when p is greater than q p&lt;=q : evaluates true when p is less than or equal to q p&gt;=q : evaluates true when p is greater than or equal to q p!=q : evaluates true when p is not equal to q p==q : evaluates true when p is equal to q


How do you construct a truth table for parenthesis not p q parenthesis if and only if p?

Assuming that you mean not (p or q) if and only if P ~(PVQ)--&gt; P so now construct a truth table, (just place it vertical since i cannot place it vertical through here.) P True True False False Q True False True False (PVQ) True True True False ~(PVQ) False False False True ~(PVQ)--&gt;P True True True False if it's ~(P^Q) --&gt;P then it's, P True True False False Q True False True False (P^Q) True False False False ~(P^Q) False True True True ~(P^Q)--&gt;P True True False False


If p is true and q is false what is the truth value or p or q?

true or false = true


What is the law f detachment?

Law of Detachment states if p&rarr;q is true and p is true, then q must be true. p&rarr;q p therefore, q Ex: If Charlie is a sophomore (p), then he takes Geometry(q). Charlie is a sophomore (p). Conclusion: Charlie takes Geometry(q).


What is the relationship between the values p and q plotted on the number line below?

p=q


Is not p and q equivalent to not p and not q?

Think of 'not' as being an inverse. Not 1 = 0. Not 0 = 1. Using boolean algebra we can look at your question. 'and' is a test. It wants to know if BOTH P and Q are the same and if they are 1 (true). If they are not the same, or they are both 0, then the result is false or 0. not P and Q is rewritten like so: (P and Q)' = X not P and not Q is rewritten like: P' and Q' = X (the apostrophe is used for not) We will construct a truth table for each and compare the output. If the output is the same, then you have found your equivalency. Otherwise, they are not equivalent. P and Q are the inputs and X is the output. P Q | X P Q | X ------ 0 0 | 1 0 0 | 1 0 1 | 1 0 1 | 0 1 0 | 1 1 0 | 0 1 1 | 0 1 1 | 0 Since the truth tables are not equal, not P and Q is not equivalent to not P and not Q. Perhaps you meant "Is NOT(P AND Q) equivalent to NOT(P) AND NOT(Q)?" NOT(P AND Q) can be thought of intuitively as "Not both P and Q." Which if you think about, you can see that it would be true if something were P but not Q, Q but not P, and neither P nor Q-- so long as they're not both true at the same time. Now, "NOT(P) AND NOT(Q)" is clearly _only_ true when BOTH P and Q are false. So there are cases where NOT(P AND Q) is true but NOT(P) AND NOT(Q) is false (an example would be True(P) and False(Q)). NOT(P AND Q) does have an equivalence however, according to De Morgan's Law. The NOT can be distributed, but in doing so we have to change the "AND" to an "OR". NOT(P AND Q) is equivalent to NOT(P) OR NOT(Q)