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11 people in a football

Q: What does 11 P in a F S T mean?

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F-11 = 4 f-10 = 5 f-11 = 4 f-10 = 5+1 = 6 4546

11 players on a soccer team.

The answer depends on the distribution of the random variable. For some variables it is easy to calculate the cumulative distribution, F(x).Then, the probability between the values p and q is F(q) - F(p). WARNING: This might need minor modification if the the distribution is discrete.The normal distribution is one which, in general, cannot be evaluated analytically. However, you can convert p and q to the x=corresponding z-score. If m is the mean and s the standard deviations, then z1 = (p - m)/s and z2 = (q - m)/s. The cumulative probability function for Z is tabulated (widely available online) and the probability between p and q is F(z2) - F(z1).Note, however, that sometimes the tabulated values are (Prob - 0.5), or are 1 - Prob(z) so read notes to the table.

25+11=36: Let f and s represent the first and second numbers respectively. The statement of the problem yields two equations: f + s =36 and f = 3 + 2s. Substituting the function given in the second equation for f into the first equation yields 3 + 2s + s = 36, or (subtracting 3 from each side and merging the s terms, 3s = 33 or s = 11. Then f + 11 = 36 (substituting the value for s into the first equation), or f = 25.

P is a permutation. It is asking for the numbers in the ()'s after it. For exapmle, P(6,4) is 6x5x4 which is 120.

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8 s on a ss= 8 sides on a stop sign

The answer is: S,P,D,F. Beyond F they follow normal alphabetic order: G, H, I, etc.

Energy Level: Sublevels1: s2: s, p3: s, p, d4: s, p, d, f5: s, p, d, f, g6: s, p, d, f, g, h7: s, p, d, f, g, h, i

s = ? , p=? , d=?, f=?

P-S , H-F, P-Cl

11 players in a soccer team