16
13 = 12x - 2y Adding 2y to both sides: 13 + 2y = 12x Subtracting 13 from both sides: 2y = 12x - 13 Divide both sides by 2: y = 6x - 6.5
6x2 + 7x = 56x2 + 7x - 5 = 0x =[ -7 ± √[72 - 4(6)(-5)] ]/2(6)x = [-7 ± √(49 + 120)]/12x = (-7 ± √ 169)/12x = (-7 ± 13)/12x = (-7 + 13)/12 or x = (-7 - 13)/12x = 6/12 = 1/2 orx = -20/12 = - 5/3
good question! Any variable (x,y,z) having power zero is equal to one........... since, 12x0=?? 12(1) since x0=1 thus 12 is the answer
2*2 - 12x +16 =0 4 - 12x +16 =0 -12x + 16 +4 =0 -12x + 20 =0 -12x = -20 x = 1.666666667
13
16
13 = 12x - 2y Adding 2y to both sides: 13 + 2y = 12x Subtracting 13 from both sides: 2y = 12x - 13 Divide both sides by 2: y = 6x - 6.5
If this is algebra then; 3x plus 12x = 15x
x2+12x-13=0 The factor of x2+12x-13 is: (x+13)(x-1) So: x+13 = 0 or x-1 = 0 The answer is: x=-13 or x=1
0
-60x
12x - 4 = 7x - 21 12x -7x = -21 + 4 5x = -17 x = -3.4
17
It is: 12x
20
X=.75