Do you mean 23 P of C in the H B? 23 Pairs of chromosomes in the human body.
Area = square root of {s1(s1-a)(s1-b)(s1-p)} + square root of {s2(s2-c)(s2-d)(s2-p)} where a,b,c and d are the four sides of the quadrilateral, p is the diagonal separating the sides a,b from c,d, and s1 = (a+b+p)/2 and s2 = (c+d+p)/2
16 balls in pool including the cue ball
24 black birds in a pie
I think it's something like a + b + c. side + side + side. Just adding them all together.
Do you mean 23 P of C in the H B? 23 Pairs of chromosomes in the human body.
p=a+b+c for a
p=b+3a+c p-3a-c=b+3a-3a+c-c p-3a-c=b b=p-3a-c
Area of triangle = sqrt[p/2*(p/2-a)*(p/2-b)*(p/2-c)] where a, b and c are the sides.
P = a + b + c + d, where a, b, c, d are sides. P = 2 × (a + b), where a and b are adjacent sides. P=2*(15.1+16) P=2*31.1 P=62.2 Answer: P= 62.2
A subset C of set B associated with the topological space B, D is said to be open if at any point c Є C there exists a positive number p such that the D-p neighborhood N(x, p) ⊂ C.See related links for more information and definitions.
is it illegal to put a squirrel in a t-shirt cannon and shoot it at a pedestrian
Area = square root of {s1(s1-a)(s1-b)(s1-p)} + square root of {s2(s2-c)(s2-d)(s2-p)} where a,b,c and d are the four sides of the quadrilateral, p is the diagonal separating the sides a,b from c,d, and s1 = (a+b+p)/2 and s2 = (c+d+p)/2
-(b + c - p - 2q)(b + c + p + 2q)
c.23
A D-p neighborhood is the set of all the points within a given metric space that are a distance p away from a chosen point within the metric space. This is described mathematically below:Let B, D be a metric space, p be any positive number, and b, c Є B. Then the D-pneighborhood of b is all the points c where D(b, c) < p.In set theory notation, the above can be written as {c Є B | D(b, c) < p}.A D-p neighborhood of b is often notated as N(b, p).See related links for further information
Consider the three events: A = rolling 5, 6, 8 or 9. B = rolling 7 C = rolling any other number. Let P be the probability of these events in one roll of a pair of dice. Then P(A) = P(5) + P(6) + P(8) + P(9) = 18/36 = 1/2 P(B) = P(7) = 6/36 = 1/6 and P(C) = 1 - [P(A) + P(B)] = 1/3 Now P(A before B) = P(A or C followed by A before B) = P(A) + P(C)*P(A before B) = 1/2 + 1/3*P(A before B) That is, P(A before B) = 1/2 + 1/3*P(A before B) or 2/3*P(A before B) = 1/2 so that P(A before B) = 1/2*3/2 = 3/4