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23 pairs of chromosomes in the human body

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Q: What does 23 P OF C IN The h b mean?
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What is 24 P of C in the H B?

Do you mean 23 P of C in the H B? 23 Pairs of chromosomes in the human body.


What does 50 P for a B E mean?

p=a+b+c for a


P equals b plus 3a plus c solve for b?

p=b+3a+c p-3a-c=b+3a-3a+c-c p-3a-c=b b=p-3a-c


What is the formula to the triangle involving perimeter?

Area of triangle = sqrt[p/2*(p/2-a)*(p/2-b)*(p/2-c)] where a, b and c are the sides.


What is the perimeter of a rectangle that is 15.1 m by 16 m?

P = a + b + c + d, where a, b, c, d are sides. P = 2 × (a + b), where a and b are adjacent sides. P=2*(15.1+16) P=2*31.1 P=62.2 Answer: P= 62.2


What does it mean for a subset to be open?

A subset C of set B associated with the topological space B, D is said to be open if at any point c Є C there exists a positive number p such that the D-p neighborhood N(x, p) ⊂ C.See related links for more information and definitions.


. If A and B are two events in the same sample space such that P(A) = 0.52, P(B) = 0.44 and P( A ∩ B) = 0.21, find:a. P( A  B )b. P( A’ ∩ B’)c. P( B’\ A’)d. P(A and B’ )?

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Area = square root of {s1(s1-a)(s1-b)(s1-p)} + square root of {s2(s2-c)(s2-d)(s2-p)} where a,b,c and d are the four sides of the quadrilateral, p is the diagonal separating the sides a,b from c,d, and s1 = (a+b+p)/2 and s2 = (c+d+p)/2


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Which number is a prime number a.14 b.15 c.23 d.25?

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What is a D-p neighborhood in topology?

A D-p neighborhood is the set of all the points within a given metric space that are a distance p away from a chosen point within the metric space. This is described mathematically below:Let B, D be a metric space, p be any positive number, and b, c &Atilde;&#144;&acirc;&euro;&#382; B. Then the D-pneighborhood of b is all the points c where D(b, c) < p.In set theory notation, the above can be written as {c &Atilde;&#144;&acirc;&euro;&#382; B | D(b, c) < p}.A D-p neighborhood of b is often notated as N(b, p).See related links for further information


What is the probability of rolling either a 5 or 6 or 8 or 9 before rolling a 7 with two dice?

Consider the three events: A = rolling 5, 6, 8 or 9. B = rolling 7 C = rolling any other number. Let P be the probability of these events in one roll of a pair of dice. Then P(A) = P(5) + P(6) + P(8) + P(9) = 18/36 = 1/2 P(B) = P(7) = 6/36 = 1/6 and P(C) = 1 - [P(A) + P(B)] = 1/3 Now P(A before B) = P(A or C followed by A before B) = P(A) + P(C)*P(A before B) = 1/2 + 1/3*P(A before B) That is, P(A before B) = 1/2 + 1/3*P(A before B) or 2/3*P(A before B) = 1/2 so that P(A before B) = 1/2*3/2 = 3/4