Add together the individual numerals (M = 1000, D = 500, C = 100, L = 50, X = 10, V = 5, I = 1) unless a smaller numeral precedes a larger one in which case subtract it from the larger one.
→ IX = (-1 + 10) = 9.
They are the Roman numerals for 9, 10, 16 and 17.
The given Roman numerals are equivalent to 62 divided by 9 which is 6 and 8/9 or 6.'8' recurring '8'
2005
how do you take one away from nine and leave ten
In modern day notation of Roman numerals MCMLXIII is the equivalent of 1963 but the ancient Romans would have probably expressed it quite differently
NO!!!! 'IX = 9 However 'XI = 11 In Roman numerals The letters corresponding to their values are M = 1000 D = 500 C = 100 L = 50 X = 10 V = 5 I = 1 The highest value letter ALWAYS goes to the left , except for subtraction. So in you example IX , the I =1 is of lesser value than X = 10 . Hence when this lesset value letter is placed to the left of a higher value letter it means 'subtract'. So ;IX' means 10 - 1 = 9 However, 'XI = 10 + 1 = 11 Similarly MM = 1000 + 1000 = 2000 But MCM = 1000 + ( 1000 - 100) = 1000 + 900 = 1900. So the years 2025 is = MMXXV However the year 1925 = MCMXXV
9 in Roman numerals is written as IX.
XXIIX-IX-IXImproved Answer:-In today's notation of Roman numerals it is: XXVIII-IX-IX
In today's notation of Roman numerals: IX-IX-MCMLXXXVIII
It is already in Roman numerals as IX which means 10-1 = 9
IX in roman numerals represents the number 9
The Roman numeral IX is 9.
It is 911. IX = 9 XI = 11
109. (c = 100, ix = 9)
09 in Roman Numerals is written as IX
IX-IX-IX or VIIII-VIIII-VIIII
IX