They are the Roman numerals for 9, 10, 16 and 17.
Add together the individual numerals (M = 1000, D = 500, C = 100, L = 50, X = 10, V = 5, I = 1) unless a smaller numeral precedes a larger one in which case subtract it from the larger one. → IX = (-1 + 10) = 9.
how do you take one away from nine and leave ten
In today's terms 98 expressed in Roman numerals is XCVIII But the rules governing the Roman numeral system were introduced during the Middle Ages centuries after the decline of the Roman Empire. Therefore it follows that the Romans themselves would have probably wrote out 98 as LXXXXVIII which can be simplified to IIC in the same way as the Roman numerals IIII and VIIII (4 and 9) are simplified to IV and IX respectively. In parts of Spain the numerals for VIII (8) are written out as IIX.
It is: 9 because IX means 10-1 = 9
9
It is: X-IX-MMXII
It was once VIIII and later simplified to IX (10-1)
9 in Roman numerals is written as IX.
XXIIX-IX-IXImproved Answer:-In today's notation of Roman numerals it is: XXVIII-IX-IX
IX-IX-IX or VIIII-VIIII-VIIII
In today's notation of Roman numerals: IX-IX-MCMLXXXVIII
No, IX - 9
9
It is already in Roman numerals as IX which means 10-1 = 9
No, IX = 9 11 = XI
The modern numeral for IX is 9.