4c+2 = 3c+9 4c-3c = 9-2 c = 7
17-3= 4c+3c c=2
3c+6=18 3c+6-6=18-6 3c=12 3c÷3=12÷3 c=4
well it could be anything, but I think you are thinking of Pythagoras' theorem. a(2) x b(2) = c(2) (2) = squared
3c - 4d = 6d + 4c Subtract 4c from both sides: -c - 4d = 6d Add 4d to both sides: -c = 10d or c = - 10d
3c - 12 = 14 + 5cSubtract 3c from each side:-12 = 14 + 2cSubtract 14 from each side:-26 = 2cDivide each side by 2:-13 = c
36-4c-3c=22 -7c=22-36 -7c=-14 therefore c=2
4c+2 = 3c+9 4c-3c = 9-2 c = 7
17-3= 4c+3c c=2
4 + 3c = 2c + 2Subtract 4 from each side:3c = 2c - 2Subtract 2c from each side:c = -2
If: 3c = 6Then: c = 2
3c-25=17-c 3c+c=25+17 4c=42 c=10.5
C = 5
3c+6=18 3c+6-6=18-6 3c=12 3c÷3=12÷3 c=4
If 3c equals 1pt, then 1 cup (c) would be equal to 1/3 pint (pt).
It is:- 3c+5 = c+15 Subtact 5 and c from both sides: 2c = 10 Divide both sides by 2 to find the value of c: c = 5
You mean: 39=3c 13=c