Add together the individual numerals (M = 1000, D = 500, C = 100, L = 50, X = 10, V = 5, I = 1) unless a smaller numeral precedes a larger one in which case subtract it from the larger ones.
→ CCX = 100 + 100 + 10 = 210.
2005
In modern day notation of Roman numerals MCMLXIII is the equivalent of 1963 but the ancient Romans would have probably expressed it quite differently
It is: 205 = CCV in Roman numerals
We do use Roman numerals today. For example, Roman numerals are often found in making outlines; to label book chapters; to label the frontmatter (pages) in books.
The Roman numerals for 64 are ILXV (65-1) or LXIIII (64) and they are not LXIV. So your question is: What is the cube root of LXIIII in Arabic numerals? The answer is 4 which is IIII or IV in Roman numerals.
The Roman numerals of CCX are the equivalent of 210 in Hindu-Arabic numerals.
210
It is: 210 = CCX
Exactly as in the question but if you mean in Roman numerals they are CDXXXVI, DX and CCX respevtively
They are: CDXXXVI, DX and CCX respectively
It is: (M)CCX which means 1000*1000+210 = 1,000,210
It is: (VII)CCX = 1000*7+210 = 7210
They are: (V)CCX which means 1000*5+200+10 = 5210
It is: CCX = 210
2x3x5x7 = 210 II*III*V*VII = CCX
To find the missing number in the sequence "clclxx cxc ccx," we first convert the Roman numerals to Arabic numerals. "clclxx" represents 170, "cxc" represents 190, and "ccx" represents 210. The numbers increase by 20 each time, so the missing number between 170 and 190 is 180. Therefore, the missing number is 180.
988 = CMLXXXVIII in Roman numerals