The mean and standard deviation. If the data really are normally distributed, all other statistics are redundant.
The means of repeated samples from any population.
no
The z score is (1650-1500)/150 = 150/150 = 1
The cause of skewed data distributions are extreme values, also know as outliers. For example imagine taking the weights of people you see on the street. If you have 9 cheerleaders' weights and then the weight of a sumo wrestler mixed into the averages this skews the data. This makes the mean much higher because of the one extreme value. Instead of the data being distributed normally, it is distributed with a positive skew. If there is a really small extreme value instead of a really large one, then the data has a negative skew. This could be the heights of people on the street, but one of them would be a midget. The mean is made lower by that one extreme value. Perhaps, little person is a more politically correct term in our day.
The mean and standard deviation. If the data really are normally distributed, all other statistics are redundant.
The easiest way to tell if data is normally distributed is to plot the data.line plot apex
The form of this question incorportates a false premise. The premise is that the data are normally distributed. Actually, is the sample mean which, under certain circumstances, is normally distributed.
Why wood u say that because that .
In a normally distributed data set, approximately 95% of the data falls within two standard deviations of the mean. This is part of the empirical rule, which states that about 68% of the data falls within one standard deviation and about 99.7% falls within three standard deviations. Therefore, two standard deviations capture a significant majority of the data points.
In a normal distribution the mean, median and mode are all the same value.
Yes. The transform is z= (x-xbar)/s where x is the data value, xbar is the mean of the data and s is the standard deviation.
Also normally distributed.
The most appropriate measures of center for a data set depend on its distribution. If the data is normally distributed, the mean is a suitable measure of center; however, if the data is skewed or contains outliers, the median is more appropriate. For measures of spread, the standard deviation is ideal for normally distributed data, while the interquartile range (IQR) is better for skewed data or when outliers are present, as it focuses on the middle 50% of the data.
The means of repeated samples from any population.
Whether or not the data are normally distributed and the Customer expectations.
it must be normally distributed