answersLogoWhite

0

What does n and x in nx(n-1) mean?

Updated: 4/28/2022
User Avatar

Wiki User

8y ago

Best Answer

With no context it is difficult to be sure but I suggest that n is a counter: a variable that goes 1, 2, 3, 4, ...and x, unfortunately, represents multiplication. I say unfortunately because the accepted symbol nowadays is * rather than x.


So the expression is to multiply a number by its predecessor. The expression could represent the number of permutations of two objects selected from n distinct objects.

User Avatar

Wiki User

8y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What does n and x in nx(n-1) mean?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

Formula of mean absolute deviation?

Mean absolute deviation = sum[|x-mean(x)|]/n Where mean(x) = sum(x)/n and n is the number of observations. |y| denotes the absolute value of y.


What happens to mean when any score in a distribution is changed?

If there are n scores and one score is changed by x then the mean changes by x/n.


What if you have the mean and then 2 more numbers how do you find the new mean?

You can only answer this question if you know how many numbers there were before. (If you know how many were there after, then subtracting two gives you the number before). So suppose there were n numbers with mean x. And you add two more numbers, a and b. That means the sum of the n numbers was n*x. Sum of the n+2 numbers is n*x + a + b So the new mean is (n*x + a + b)/(n + 2)


What does x equals 2n mean?

It means that the variable x is twice as much as variable n. x is in direct proportion to n (or x varies directly as n) with the constant of proportionality = 2.


What is the n in x incicating the number of factors of x?

not able to know what you mean?


The mean of n numbers is 5 If the number 13 is now included with the n numbers the new mean is 6 Find the value of n?

The mean of N numbers is the sum of those numbers divided by N. If you include 13 in that set and the new mean is 6, then the original N is 7. Let X be the original sum. You have a system of two simultaneous equations. 1.) X/N = 5 2.) X+13/N+1 = 6 To solve, substitute the value of X from eq. 1 into eq. 2 and then solve eq. 2 for N. (Some steps combined) X = 5N5N+13 = 6(N+1)5N = 6N-7-N = -7N = 7


What are the mean and the standard deviation of a proportion?

The mean of a proportion, p, is X/n; where X is the number of instances & n is the sample size; and its standard deviation is sqrt[p(1-p)]


What are the law of exponent?

Exponents are subject to many laws, just like other mathematical properties. These are X^1 = X, X^0 = 1, X^-1 = 1/X, X^m * X^n = X^m+n, X^m/X^n = X^m-n, (X^m)^n = X^(m*n), (XY)^n = X^n * Y^n, (X/Y)^n = X^n/Y^n, and X^-n = 1/X^n.


How do you write 7 x n x n x n x n x n in exponential notation?

7 x n^5


What is the answer of 1 divide by x square?

What do you mean? As this is a calculus question, I presume that you are asking for a derivative or integral The derivative of any function of the form ƒ(x) = a * x ^ n is ƒ'(x) = a * n * x ^ (n-1) The integral of any function of the form ∫ a*x ^ n is a / (n+1) * x ^ (n+1) + C Your function that you gave is 1 / x^(2) which is equal to: x^(-2) Thus the derivative is: -2 * x^(-3) And the integral is: -x^(-1) + C


What are the different law of exponent?

Exponents are subject to many laws, just like other mathematical properties. These are X^1 = X, X^0 = 1, X^-1 = 1/X, X^m * X^n = X^m+n, X^m/X^n = X^m-n, (X^m)^n = X^(m*n), (XY)^n = X^n * Y^n, (X/Y)^n = X^n/Y^n, and X^-n = 1/X^n.


What are different laws of exponents?

Exponents are subject to many laws, just like other mathematical properties. These are X^1 = X, X^0 = 1, X^-1 = 1/X, X^m * X^n = X^m+n, X^m/X^n = X^m-n, (X^m)^n = X^(m*n), (XY)^n = X^n * Y^n, (X/Y)^n = X^n/Y^n, and X^-n = 1/X^n.