With no context it is difficult to be sure but I suggest that n is a counter: a variable that goes 1, 2, 3, 4, ...and x, unfortunately, represents multiplication. I say unfortunately because the accepted symbol nowadays is * rather than x.
So the expression is to multiply a number by its predecessor. The expression could represent the number of permutations of two objects selected from n distinct objects.
It means that the variable x is twice as much as variable n. x is in direct proportion to n (or x varies directly as n) with the constant of proportionality = 2.
Saying that "X is the common logarithm of N" means that 10 raised to the power of X is N, or 10X = N. For instance, the common logarithm of 100 is 2, of 1000 is 3, and of 25 is about 1.398.
n squared x n n x n x n = n cubed n x n = n squared n squared x n = n cubed
Factorial. n! = 1x2x3x4x.....x(n-2)x(n-1)xn. Examples: 3! = 1x2x3 = 6 7! = 1x2x3x4x5x6x7=5040
In mathematics, XN typically represents a variable (X) raised to a power (N). This is known as exponentiation, where X is the base and N is the exponent. The expression XN is equal to multiplying X by itself N times. For example, X2 means X squared, which is X multiplied by itself two times.
Mean absolute deviation = sum[|x-mean(x)|]/n Where mean(x) = sum(x)/n and n is the number of observations. |y| denotes the absolute value of y.
If there are n scores and one score is changed by x then the mean changes by x/n.
You can only answer this question if you know how many numbers there were before. (If you know how many were there after, then subtracting two gives you the number before). So suppose there were n numbers with mean x. And you add two more numbers, a and b. That means the sum of the n numbers was n*x. Sum of the n+2 numbers is n*x + a + b So the new mean is (n*x + a + b)/(n + 2)
It means that the variable x is twice as much as variable n. x is in direct proportion to n (or x varies directly as n) with the constant of proportionality = 2.
not able to know what you mean?
The mean of N numbers is the sum of those numbers divided by N. If you include 13 in that set and the new mean is 6, then the original N is 7. Let X be the original sum. You have a system of two simultaneous equations. 1.) X/N = 5 2.) X+13/N+1 = 6 To solve, substitute the value of X from eq. 1 into eq. 2 and then solve eq. 2 for N. (Some steps combined) X = 5N5N+13 = 6(N+1)5N = 6N-7-N = -7N = 7
The mean of a proportion, p, is X/n; where X is the number of instances & n is the sample size; and its standard deviation is sqrt[p(1-p)]
Exponents are subject to many laws, just like other mathematical properties. These are X^1 = X, X^0 = 1, X^-1 = 1/X, X^m * X^n = X^m+n, X^m/X^n = X^m-n, (X^m)^n = X^(m*n), (XY)^n = X^n * Y^n, (X/Y)^n = X^n/Y^n, and X^-n = 1/X^n.
7 x n^5
What do you mean? As this is a calculus question, I presume that you are asking for a derivative or integral The derivative of any function of the form ƒ(x) = a * x ^ n is ƒ'(x) = a * n * x ^ (n-1) The integral of any function of the form ∫ a*x ^ n is a / (n+1) * x ^ (n+1) + C Your function that you gave is 1 / x^(2) which is equal to: x^(-2) Thus the derivative is: -2 * x^(-3) And the integral is: -x^(-1) + C
Saying that "X is the common logarithm of N" means that 10 raised to the power of X is N, or 10X = N. For instance, the common logarithm of 100 is 2, of 1000 is 3, and of 25 is about 1.398.
Exponents are subject to many laws, just like other mathematical properties. These are X^1 = X, X^0 = 1, X^-1 = 1/X, X^m * X^n = X^m+n, X^m/X^n = X^m-n, (X^m)^n = X^(m*n), (XY)^n = X^n * Y^n, (X/Y)^n = X^n/Y^n, and X^-n = 1/X^n.