Answer = 0 + 2 + 4 + 8 = 14
1. represent every individual digit of given hexadecimal in binary form like this 4---------> 0100 8---------> 1000 7---------> 0111 2. combine the individual binary digits in order to get the binary of given hexadecimal number 487 ------------> 0100 1000 0111 ( required binary number )
E7c3
It's 7.
At least 8 bits are needed to represent the number 231. 231 ÷ 2 = 115 r 1 115 ÷ 2 = 57 r 1 57 ÷ 2 = 28 r 1 28 ÷ 2 = 14 r 0 14 ÷ 2 = 7 r 0 7 ÷ 2 = 3 r 1 3 ÷ 2 = 1 r 1 1 ÷ 2 = 0 r 1 → 231 is 1110 0111 in binary and has 8 binary digits. Thus 231 can be represented in 8 bits, but if more are provided, eg 16, it can still be represented (in 16 bits it would be 0000 0000 1110 0111, unless there is a binary point, with say 8 bits after it, then 231 would be 1110 0111 . 0000 0000).
The binary number 10000000 represents the decimal 128
1. represent every individual digit of given hexadecimal in binary form like this 4---------> 0100 8---------> 1000 7---------> 0111 2. combine the individual binary digits in order to get the binary of given hexadecimal number 487 ------------> 0100 1000 0111 ( required binary number )
1110 0111 1100 00112 is not a binary number as it has three different symbols
When you write the decimal number '7' in Base-2 (binary), you write '0111'.
E7c3
The answer is 1 0101 0111 1110 1011 1011 0011 1111 1010 0001 0111
To represent the decimal number 47 in Binary-Coded Decimal (BCD), you first separate the digits: 4 and 7. In BCD, each digit is represented by its 4-bit binary equivalent. Therefore, 4 is represented as 0100 and 7 as 0111. Combining these, 47 in BCD is expressed as 0100 0111.
It's 7.
When the binary number 0111 is incremented by one, it becomes 1000. This is because adding one to 0111 (which represents 7 in decimal) results in 1000, which represents 8 in decimal. The increment causes a carry that changes the last three bits to 0 and adds a 1 to the next left position.
11 and 7 (if you mean two separate 4-digit binary numbers) or 227 as one 8-digit binary number.
At least 8 bits are needed to represent the number 231. 231 ÷ 2 = 115 r 1 115 ÷ 2 = 57 r 1 57 ÷ 2 = 28 r 1 28 ÷ 2 = 14 r 0 14 ÷ 2 = 7 r 0 7 ÷ 2 = 3 r 1 3 ÷ 2 = 1 r 1 1 ÷ 2 = 0 r 1 → 231 is 1110 0111 in binary and has 8 binary digits. Thus 231 can be represented in 8 bits, but if more are provided, eg 16, it can still be represented (in 16 bits it would be 0000 0000 1110 0111, unless there is a binary point, with say 8 bits after it, then 231 would be 1110 0111 . 0000 0000).
A nibble is 4 bits, so the largest unsigned number is 1111, or 15. Also, the largest signed number is 0111, or 7.
1539026015