It's 7.
0111 = decimal 7 0011 = decimal 3 ____ 1010 = decimal 10 ____
Binary code of 4 is 0100. To get Excess-3 code, add 11(binary code of 3) to binary code of desired number, here it is 4. Hence, Excess-3 Code for 4 is 0111.
1. represent every individual digit of given hexadecimal in binary form like this 4---------> 0100 8---------> 1000 7---------> 0111 2. combine the individual binary digits in order to get the binary of given hexadecimal number 487 ------------> 0100 1000 0111 ( required binary number )
Answer = 0 + 2 + 4 + 8 = 14
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When you write the decimal number '7' in Base-2 (binary), you write '0111'.
0111 0110
1001 0111 base 2
0111 = decimal 7 0011 = decimal 3 ____ 1010 = decimal 10 ____
The answer is 1 0101 0111 1110 1011 1011 0011 1111 1010 0001 0111
When the binary number 0111 is incremented by one, it becomes 1000. This is because adding one to 0111 (which represents 7 in decimal) results in 1000, which represents 8 in decimal. The increment causes a carry that changes the last three bits to 0 and adds a 1 to the next left position.
.0111 is the largest decimal.
11 and 7 (if you mean two separate 4-digit binary numbers) or 227 as one 8-digit binary number.
To represent the decimal number 47 in Binary-Coded Decimal (BCD), you first separate the digits: 4 and 7. In BCD, each digit is represented by its 4-bit binary equivalent. Therefore, 4 is represented as 0100 and 7 as 0111. Combining these, 47 in BCD is expressed as 0100 0111.
It is: .0111 that is the largest
1110 0111 1100 00112 is not a binary number as it has three different symbols
Binary code of 4 is 0100. To get Excess-3 code, add 11(binary code of 3) to binary code of desired number, here it is 4. Hence, Excess-3 Code for 4 is 0111.