95, is the two digits after the last digit of the multiple of 5's.
95^2 = 9,025
3 units 6 tenths 4 hundredths 5 thousandths
It represent eighty thousand.
AB If B = x, then A = x + 4 Also, A = 2x -1 So that, 2x - 1 = x + 4 x = 5 B = 5, A = 9 So AB = 95
95 95/5=19
95, is the two digits after the last digit of the multiple of 5's.
No. To be divisible by 9 the sum of the digits must also be divisible by 9. As the sum must be divisible by 9, the check can also be applied to the sum; so keep summing until a single digit remains, then if, and only if, this single digit is 9 is the original number divisible by 9 (the single digit gives the remainder when the original number is divided by 9 and is known as the digital root of the number). For 95: 95 → 9 + 5 = 14 14 → 1 + 4 = 5 5 ≠ 9 → 95 is not divisible by 9. (The remainder when 95 is divided by 9 is 5).
95^2 = 9,025
3 units 6 tenths 4 hundredths 5 thousandths
It represents 0.5 which is equivalent to 1/2 = a half
100
The only two numbers that represent a binary digit are 0 and 1
It represent eighty thousand.
100
Digit 4 represents ones.
Digit four represents ones.