Add together the individual numerals (M = 1000, D = 500, C = 100, L = 50, X = 10, V = 5, I = 1) unless a smaller numeral precedes a larger one in which case subtract it from the larger ones.
→ XCII = (-10 + 100) + 1 + 1 = 92
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C represents 100 and X represents 10. Since the X comes before the C you subtract it to give 92.
2005
It is: 205 = CCV in Roman numerals
In modern day notation of Roman numerals MCMLXIII is the equivalent of 1963 but the ancient Romans would have probably expressed it quite differently
We do use Roman numerals today. For example, Roman numerals are often found in making outlines; to label book chapters; to label the frontmatter (pages) in books.
The Roman numerals for 64 are ILXV (65-1) or LXIIII (64) and they are not LXIV. So your question is: What is the cube root of LXIIII in Arabic numerals? The answer is 4 which is IIII or IV in Roman numerals.