Add together the individual numerals (M = 1000, D = 500, C = 100, L = 50, X = 10, V = 5, I = 1) unless a smaller numeral precedes a larger one in which case subtract it from the larger ones.
→ XCII = (-10 + 100) + 1 + 1 = 92
2005
It is: 205 = CCV in Roman numerals
In modern day notation of Roman numerals MCMLXIII is the equivalent of 1963 but the ancient Romans would have probably expressed it quite differently
We do use Roman numerals today. For example, Roman numerals are often found in making outlines; to label book chapters; to label the frontmatter (pages) in books.
The Roman numerals for 64 are ILXV (65-1) or LXIIII (64) and they are not LXIV. So your question is: What is the cube root of LXIIII in Arabic numerals? The answer is 4 which is IIII or IV in Roman numerals.
For these numerals to make any sense arrange them in descending order like this: CLLLX which can be simplified to CCLX (260)
988 = CMLXXXVIII in Roman numerals
it means 1,150 in roman numerals
Those Roman Numerals mean 1991.
Not a valid sequence for Roman numerals
It does not mean anything because it is an invalid arrangement of Roman numerals
"D" in Roman Numerals equals 500.
Roman numerals don't have a 0 symbol and so it is an invalid arrangement of Roman numerals
In Roman numerals, it means N M C.
XL1 in roman numerals stand for 41.
The Roman numerals MCMXCVI stands for 1996
The given Roman numerals are equivalent to 1112