Let the five consecutive numbers be represented as n-2, n-1, n, n+1, and n+2. The sum of these numbers can be expressed as (n-2) + (n-1) + n + (n+1) + (n+2) = 5n. Setting this sum equal to 100 gives us 5n = 100. Solving for n, we find n = 20. Therefore, the five consecutive numbers that add up to 100 are 18, 19, 20, 21, and 22.
The numbers are 21, 22, 23, 24, and 25.
28
98, 100, 102
This has no answer. Any five odd numbers will always add to an odd number. 100 is even.
Let the consecutive numbers be n,n+1, n+2, n+3, & n+ 4. Add n + (n+1)+(n+2) + (n + 3) + ( n + 4) = 115 5n + 10 = 115 5n = 105 n = 21 N+1 = 22 n+2 = 23 n+3 = 24 n + 4 = 25 So the five consecutive numbers are 21,22,23,24 & 25.
The five consecutive numbers that add up to 100 are 18, 19, 20, 21, and 22. When you add these numbers together (18 + 19 + 20 + 21 + 22), the sum equals 100.
The numbers are 16, 18, 20, 22 and 24.
The numbers are 21, 22, 23, 24, and 25.
28
98, 100, 102
97, 98, 99 and 100.
This has no answer. Any five odd numbers will always add to an odd number. 100 is even.
15, 17, 19, 21 and 23.
Let the consecutive numbers be n,n+1, n+2, n+3, & n+ 4. Add n + (n+1)+(n+2) + (n + 3) + ( n + 4) = 115 5n + 10 = 115 5n = 105 n = 21 N+1 = 22 n+2 = 23 n+3 = 24 n + 4 = 25 So the five consecutive numbers are 21,22,23,24 & 25.
16,25,36 add to 77. They are the squares of consecutive numbers 4,5,6
104
Consecutive whole numbers will have an odd sum. Consecutive odd numbers, or consecutive prime numbers, will be 29 and 31.