Let the five consecutive numbers be represented as n-2, n-1, n, n+1, and n+2. The sum of these numbers can be expressed as (n-2) + (n-1) + n + (n+1) + (n+2) = 5n. Setting this sum equal to 100 gives us 5n = 100. Solving for n, we find n = 20. Therefore, the five consecutive numbers that add up to 100 are 18, 19, 20, 21, and 22.
The numbers are 21, 22, 23, 24, and 25.
28
98, 100, 102
This has no answer. Any five odd numbers will always add to an odd number. 100 is even.
Let the consecutive numbers be n,n+1, n+2, n+3, & n+ 4. Add n + (n+1)+(n+2) + (n + 3) + ( n + 4) = 115 5n + 10 = 115 5n = 105 n = 21 N+1 = 22 n+2 = 23 n+3 = 24 n + 4 = 25 So the five consecutive numbers are 21,22,23,24 & 25.
The numbers are 16, 18, 20, 22 and 24.
The numbers are 21, 22, 23, 24, and 25.
28
98, 100, 102
97, 98, 99 and 100.
This has no answer. Any five odd numbers will always add to an odd number. 100 is even.
15, 17, 19, 21 and 23.
Let the consecutive numbers be n,n+1, n+2, n+3, & n+ 4. Add n + (n+1)+(n+2) + (n + 3) + ( n + 4) = 115 5n + 10 = 115 5n = 105 n = 21 N+1 = 22 n+2 = 23 n+3 = 24 n + 4 = 25 So the five consecutive numbers are 21,22,23,24 & 25.
16,25,36 add to 77. They are the squares of consecutive numbers 4,5,6
104
Consecutive whole numbers will have an odd sum. Consecutive odd numbers, or consecutive prime numbers, will be 29 and 31.
There are no four consecutive whole numbers that add up to 35. The sum of two consecutive [whole] numbers is an even number plus an odd number which is an odd number. The sum of two consecutive numbers and the two next consecutive numbers is the sum of two odd numbers which is even, but 35 is odd, so no four consecutive whole numbers cannot add up to 35.