Let the five consecutive numbers be represented as n-2, n-1, n, n+1, and n+2. The sum of these numbers can be expressed as (n-2) + (n-1) + n + (n+1) + (n+2) = 5n. Setting this sum equal to 100 gives us 5n = 100. Solving for n, we find n = 20. Therefore, the five consecutive numbers that add up to 100 are 18, 19, 20, 21, and 22.
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The numbers are 21, 22, 23, 24, and 25.
28
98, 100, 102
This has no answer. Any five odd numbers will always add to an odd number. 100 is even.
16,25,36 add to 77. They are the squares of consecutive numbers 4,5,6