Let the consecutive numbers be n,n+1, n+2, n+3, & n+ 4. Add n + (n+1)+(n+2) + (n + 3) + ( n + 4) = 115 5n + 10 = 115 5n = 105 n = 21 N+1 = 22 n+2 = 23 n+3 = 24 n + 4 = 25 So the five consecutive numbers are 21,22,23,24 & 25.
18 + 19 + 20 + 21 + 22 = 100
16,25,36 add to 77. They are the squares of consecutive numbers 4,5,6
Consecutive whole numbers will have an odd sum. Consecutive odd numbers, or consecutive prime numbers, will be 29 and 31.
There are no four consecutive whole numbers that add up to 35. The sum of two consecutive [whole] numbers is an even number plus an odd number which is an odd number. The sum of two consecutive numbers and the two next consecutive numbers is the sum of two odd numbers which is even, but 35 is odd, so no four consecutive whole numbers cannot add up to 35.
Let the consecutive numbers be n,n+1, n+2, n+3, & n+ 4. Add n + (n+1)+(n+2) + (n + 3) + ( n + 4) = 115 5n + 10 = 115 5n = 105 n = 21 N+1 = 22 n+2 = 23 n+3 = 24 n + 4 = 25 So the five consecutive numbers are 21,22,23,24 & 25.
113, 114, 115
The numbers are 16, 18, 20, 22 and 24.
18 + 19 + 20 + 21 + 22 = 100
15, 17, 19, 21 and 23.
16,25,36 add to 77. They are the squares of consecutive numbers 4,5,6
Consecutive whole numbers will have an odd sum. Consecutive odd numbers, or consecutive prime numbers, will be 29 and 31.
There is no set of three consecutive whole numbers that add up to 154.
23*5 = 115 So pick any four numbers: integers, fractions, irrational numbers, whatever. Add them together to give a sum S. Let the 5th number be 115 - S Then: sum of all five numbers = (sum of the first four numbers) + (the fifth number) = S + (115 - S) = 115 And the count of numbers = 5 So mean = Sum/Count = 115/5 = 23
There are no four consecutive whole numbers that add up to 35. The sum of two consecutive [whole] numbers is an even number plus an odd number which is an odd number. The sum of two consecutive numbers and the two next consecutive numbers is the sum of two odd numbers which is even, but 35 is odd, so no four consecutive whole numbers cannot add up to 35.
The consecutive numbers that have a sum of 257 are 128 and 129.
There are no two consecutive numbers that add or multiply to 102.