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A bag contains 3 red marbles 2 blue marbles and 5 green marbles What is the probability of selecting a red marble without replacing it in the bag and then selecting a green marble?
Total marbles in the bag = 10Number of red ones = 3Probability of pulling a red one on the first draw = 3/10 = 0.3Total marbles remaining after the first draw = 9Number of green ones = 5Probability of pulling a green one after a red one has been withdrawn = 5/9Probability of both outcomes = (3/10) x (5/9) = (15/90) = 1/6 = (16 and 2/3) percent.
What is the probability that a marble drawn at random is not red if a jar contains 3 red 4 blue and 2 white marbles?
i think 6 out of 9 right? then you simplify to equal 1 out of 3.:)
Simplify the fraction of 3 over 9?
Because 3 and 9 are both divisible by 3, we can simplify this fraction into 1/3.
A bag contains 8 red marbles 6 blue marbles and 9 green marbles If a marble is selected at random what is the probability of choosing a blue marble?
Number of different possible choices = 8 + 6 + 9 = 23Number of available successful choices (blue marbles) = 6Probability of success = 6/23 = 0.26087 = 26.087 %(rounded)
What does 3 ninths equal to as a fraction?
3 ninths is a fraction but it can be simplified to one third
