Length is multiplied by two: x 2
Height is multiplied by two: x 2
Width is multiplied by three: x 3
So, altogether equals: Original Volume x 2 x 2 x 3 = 12 times bigger.
If the radius of a circle is tripled, how is the length of the arc intercepted by a fixed central angle changed?
Area = length*width new Area = 2 * length * width Area is doubled
A 3-Dimensional box's volume will double for each dimension that is doubled. i.e. if just the height, length or depth are doubled, the volume increases 200%, if 2 of those dimensions are doubled the volume increases by 400%. if all 3 are double the volume increases by 800%.
the perimeter will double. but the area should doubled to four
300% The volume of the original box is ?. The volume of the box with the length and depth doubled is ?. The amount of change in volume is 60 - 15 = 45. The percent change is the amount of change in volume divided by the original volume:
The volume is doubled.
its volume is also doubled...
just did this on castle learning the answer is six times
well...if it's doubled then its doubled (just treat it the same)
The volume of the box will be multiplied byeight.
tripled
If the radius of a circle is tripled, how is the length of the arc intercepted by a fixed central angle changed?
The volume becomes 12 times as large.
If only the length is doubled, the volume is also doubled.If only the length is doubled, the volume is also doubled.If only the length is doubled, the volume is also doubled.If only the length is doubled, the volume is also doubled.
I believe it is 30ft, as this is the length for the previous models. However, with the internet capability, its possible that that length is doubled or tripled. You could test it.
if length and width are doubled then the volume should mulitiply by 8
If the length is tripled but the width remains unchanged, then the area is tripled.