x
This is the same thing as square root of x.
Negative one half to the fourth power equals 0.0625
find the derivative of y=x(1-x to the power 2 ) square/(1+xto the power2)half first take the natural logarithms of the absolute values of both sides ln, the absolute value of y=ln the absolute value of x(1-x to the power2) to the power two/(1+x to the power two) to the power half=... . then take the derivatives of both sides 1/y y`=1/x+2/1-x to the power two (-2x)-1/2... .
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The square root is the same as raising to the one-half power x tot he power of 8 tot he power of 8 to the power of one-half is x to the 32 power (x to the 8x8x1/2)
The square root of x to the seventeenth power is x to the eighth and a half power. If x is negative, the answer is imaginary.
I'll say no. Let's look at it: Try to make the first part rearrange to look like: 2 / sqrt(X) = 2 / [x^(1/2)] = 2 * x^(-1/2)Half X to the power minus half could mean(Half of X) to the power (minus half) = (X/2)^(-1/2) = [(1/2)^(-1/2)] * [(X)^(-1/2)] = [(2)^(1/2)] / [(X)^(1/2)] = sqrt(2) / sqrt(X), which is not the same.If you mean Half of [X to the power (minus half)] = (1/2) * (X)^(-1/2) = (1/2) / (X)^(1/2) =1 / [2*sqrt(X)], which is not the same either.
poo you
This is the same thing as square root of x.
The square root of x = x to the power of a half
It is 1.7*10^8
0.000000476837158203125 or 4.76837158203125 x 10-7
Negative one half to the fourth power equals 0.0625
find the derivative of y=x(1-x to the power 2 ) square/(1+xto the power2)half first take the natural logarithms of the absolute values of both sides ln, the absolute value of y=ln the absolute value of x(1-x to the power2) to the power two/(1+x to the power two) to the power half=... . then take the derivatives of both sides 1/y y`=1/x+2/1-x to the power two (-2x)-1/2... .
A half mole of oxygen contains approximately 3.01 x 10^23 oxygen atoms. This is because one mole of any substance contains Avogadro's number of atoms or molecules, which is 6.022 x 10^23. So, half a mole would contain half of that amount.