find the derivative of y=x(1-x to the power 2 ) square/(1+xto the power2)half first take the natural logarithms of the absolute values of both sides ln, the absolute value of y=ln the absolute value of x(1-x to the power2) to the power two/(1+x to the power two) to the power half=... . then take the derivatives of both sides 1/y y`=1/x+2/1-x to the power two (-2x)-1/2... .
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A logarithmic equation would be any equation that includes the log function.
Well, isn't that a happy little question! To find the derivative of (x-1)^x, we'll need to use logarithmic differentiation. Start by taking the natural logarithm of both sides, then apply implicit differentiation to find the derivative. Remember, there are no mistakes, just happy little accidents in math!
None. If you have an exact relationship - whether it is linear, polynomial, logarithmic or whatever - probability has no role to play.
Logarithmic Function
One point on a logarithmic graph is not sufficient to determine its parameters. It is, therefore, impossible to answer the question.