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find the derivative of y=x(1-x to the power 2 ) square/(1+xto the power2)half first take the natural logarithms of the absolute values of both sides ln, the absolute value of y=ln the absolute value of x(1-x to the power2) to the power two/(1+x to the power two) to the power half=... . then take the derivatives of both sides 1/y y`=1/x+2/1-x to the power two (-2x)-1/2... .

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Q: What is logarithmic differentiation?
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