I dont really understand the question, but that sounds like a math term. it means negative 2, negative 3, and 2a. a is going to be a variable that you will more than likely have to solve for.
Since the question is 3(2a), then just write it out. 3(2a) is 2a+2a+2a or 6a.
The multiplicative inverse of -2a is 1/(-2a) = -1/2a
a-^2a-b^-a-b
2a + 2b = c subtract 2a from both sides 2a - 2a + 2b = c - 2a 2b = c - 2a divide both sides by 2 (2/2)b = (c - 2a)/2 b = (c - 2a)/2 --------------------
3a-2a = 1
If ba = 2a + b , then find 23 + 32 +1
To find the number of different isosceles triangles with integer side lengths and a perimeter of 23, we can denote the equal sides as ( a ) and the base as ( b ). The equation for the perimeter gives us ( 2a + b = 23 ), or ( b = 23 - 2a ). For the triangle inequality to hold, ( 2a > b ) must be satisfied, which translates to ( 2a > 23 - 2a ), leading to ( 4a > 23 ) or ( a > 5.75 ). Since ( a ) must be an integer, ( a ) can take values from 6 to 11, giving the valid pairs: (6, 11), (7, 9), (8, 7), (9, 5), (10, 3), and (11, 1). Therefore, there are 6 different isosceles triangles with integer side lengths and a perimeter of 23.
(4, 3)
Since the question is 3(2a), then just write it out. 3(2a) is 2a+2a+2a or 6a.
2a+2a-7b+7b =4a
The multiplicative inverse of -2a is 1/(-2a) = -1/2a
20 = 1Consider what is the value of 2a ÷ 2a? Any number divided by itself is 1. Thus:2a ÷ 2a = 1The law of indices says that when dividing, they are subtracted, for example:25 ÷ 22 = (2 x 2 x 2 x 2 x 2) ÷ (2 x 2) = 2 x 2 x 2 = 23 = 25-2So 2a ÷ 2a is (also):2a ÷ 2a = 2a-a = 20Since any number subtracted from itself is 0 (= a - a). This must have the same value as before, thus:20 = 1The 2 above can be replaced by any number x which means that any number to the power 0 is 1:x0 = 1
a-^2a-b^-a-b
a + a + a - 2a = 3a - 2a = a
2a + 2b = c subtract 2a from both sides 2a - 2a + 2b = c - 2a 2b = c - 2a divide both sides by 2 (2/2)b = (c - 2a)/2 b = (c - 2a)/2 --------------------
8b36
3a-2a = 1