56xy + 2y + 3x
16y^2(8y)=0? Factor out an 8y to give you 8y(2y(2))=0 Use order of operations to give you 8y(4y)=0 Distribute to give you 32y=0 and ultimately the answer will be 0 If there is a missing plus or minus operator between 16y2 and the 8y, then it can be factorised by taking out common factors: 16y2 ± 8y = 0 ⇒ 8y(2y ± 1) = 0
-2
Not sure which you mean, take your pick: (8y)3+27=(8y+3)((8y)2-3*(8y)+9)=(8y+3)(64y2-24y+9); or 8y3+27=(2y+3)(4y2-6y+9)
8y+4-2y=22
-5(x + 2y) -3x + 8y + 5 = -5x -10y -3x + 8y + 5 = -8x -2y + 5
2y+8y = 10y
9y-3y=6y; 6y+2y=8y; so your answer is 8y
56xy + 2y + 3x
If: 8y-2 = 3-2y Then: 8y+2y = 3+2 So: 10y = 5 Therefore: y = 5/10 or as a 1/2 in its simplest form
4(5 - 2y) = 20 - 8y
4xy - 2y(x + 4) = 4xy - 2xy - 8y = 2xy - 8y = 2y(x - 4)
8y-7x
(x + 2y)(3x + 8y)
16y^2(8y)=0? Factor out an 8y to give you 8y(2y(2))=0 Use order of operations to give you 8y(4y)=0 Distribute to give you 32y=0 and ultimately the answer will be 0 If there is a missing plus or minus operator between 16y2 and the 8y, then it can be factorised by taking out common factors: 16y2 ± 8y = 0 ⇒ 8y(2y ± 1) = 0
2xy - 4x plus 8y - 16 equals x plus 4 in parentheses multiplied by 2y minus 4 in parentheses. So, the factors are ( x + 4) and ( 2y - 4) .
-5y2+3x+2y