2y = -6x + 8 The y intercept occurs when x = 0 2y = 8 therefore y = 4
Let this numbers be x and y, then x + y = 52 x - y = 8 x = 8 + y x + y = 52 substitute 8 + y for x into the first equation; 8 + y + y = 52 8 + 2y = 52 subtract 8 to both sides; 2y = 44 divide by 2 to both sides; y = 22 x = 8 + y substitute 22 for y into the equation; x = 8 + 22 x = 30 Thus this numbers are 22 and 30. 22 & 30
4x+2y-8=0 2y=8-4x y=4-2x slope= -2
5y+8=7y 2y=8 y=4
2y = 8 y = 4 this is the equation of a horizontal line. The slope is 0, and the y-intercept is 4.
2y = -6x + 8 The y intercept occurs when x = 0 2y = 8 therefore y = 4
4x + 2y = -8 → 2y = -4x - 8 → y = -2x - 4
-6x-2y = 8 -2y = 6x+8 y = -3x-4 Therefore the slope is -3 and the y intercept is -4
Yes, 2y = 8 is a linear function. 2y = 8 is the same as y=8/2, or y=4, which is a vertical line.
4y+4 = 2y+12 4y-2y = 12-4 2y = 8 y = 4
5x+2y>8, y≤4 5x+2(4)>8 5x+8>8 5x>0 x>0
y=4
If you mean: x+2y = 8 Then: y = -1/2x+4 Perpendicular equation: y = 2x+4
2y=8..... y=4
y2 - 2y - 8 = (y - 4)(y + 2) = 0; whence, y = 4 or -2.
Therefore, y = 4 7 + 2y = 15 7-7 + 2y = 15-7 Subtract 7 from both sides 2y = 8 Divide by 2 to get y alone 2y/2 = 8/2 y = 4
4x - 2y = 8 Rearrange into the 'straight line ' form of y = mx + c Hence -2y = -4x + 8 y = 2x - 4 The 'c' value is the y-intercept, which '-4' . The steepness/gradient of the slope is '2'.