If: 6y-3x = 18 Then: y = 0.5x+3 which is in slope-intercept form
The slope-intercept form of the equation of a line is y = mx + b, where m is the slope and b is the y-intercept. To put 3x - 2y = 16 in slope-intercept form just requires a little rearranging: 3x - 2y = 16 -2y = -3x + 16 (subtract 3x from both sides) y = 3/2x - 8 (divide all terms by -2) Now the equation is in slope-intercept form. The slope m is 3/2; the y-intercept is -8.
1
If you mean: y = -3x then the slope is -3 and there is no y intercept
Since the two lines are parallel, then they have the same slope, 3. Thus, the equation of the line with y-intercept -4, and parallel to y = 3x - 3 is y = 3x - 4.
-3
9
2y = 3x-6 y = 1.5x-3 in slope intercept form
If: 6y-3x = 18 Then: y = 0.5x+3 which is in slope-intercept form
It is: y = 0.5x-1.5 in slope intercept form
If: -3x+2y = 12 Then: y = 1.5x+6 in slope-intercept form
The slope-intercept form of the equation of a line is y = mx + b, where m is the slope and b is the y-intercept. To put 3x - 2y = 16 in slope-intercept form just requires a little rearranging: 3x - 2y = 16 -2y = -3x + 16 (subtract 3x from both sides) y = 3/2x - 8 (divide all terms by -2) Now the equation is in slope-intercept form. The slope m is 3/2; the y-intercept is -8.
5
y = 1/3x-4 in slope intercept form
y = 3x + 3 is the 'slope/intercept' form. In the general eq'n of a straight line ; y = mx + c ; The slope(m) is the coefficient of 'x' and the constant(c) is the intercept on the y-axis. So for the given eq'n , The slope is '3' and and the intercept is also '3'.
If you mean: y = -3x-2 then the slope is -3 and the y intercept is -2
I'm assuming that the entire equation is 3x + 4y = 0Here the slope is -ve 3/4 and the intercept is 0.So, the slope intercept form is y = - 3x/4 or y = - (3/4)x