The slope-intercept form of the equation of a line is y = mx + b, where m is the slope and b is the y-intercept. To put 3x - 2y = 16 in slope-intercept form just requires a little rearranging:
3x - 2y = 16
-2y = -3x + 16 (subtract 3x from both sides)
y = 3/2x - 8 (divide all terms by -2)
Now the equation is in slope-intercept form. The slope m is 3/2; the y-intercept is -8.
y = -1.2x-3 in slope intercept form
If: 6y-3x = 18 Then: y = 0.5x+3 which is in slope-intercept form
1
because right away you can tell the slope and y-intercept
12
It is in slope intercept form. The slope is 0 and the y-intercept is -2.
What is the slope-intercept form of 7x-3y equals 4
Slope-Intercept Form: y = -2x +1
y=mx+b in slope intercept form m=slope b=y-intercept
It is: y = 0.5x-1.5 in slope intercept form
2
y = -1.2x-3 in slope intercept form
-3
Slope-Intercept Form: y = -2x +1
It is: y = 0.25x-0.875 in slope intercept form
y = 6x+8 is already in slope intercept form
y = mx + b <-- (Slope Intercept equation) y = 4x - 1 <-- (Slope Intercept form)