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The slope-intercept form of the equation of a line is y = mx + b, where m is the slope and b is the y-intercept. To put 3x - 2y = 16 in slope-intercept form just requires a little rearranging:

3x - 2y = 16

-2y = -3x + 16 (subtract 3x from both sides)

y = 3/2x - 8 (divide all terms by -2)

Now the equation is in slope-intercept form. The slope m is 3/2; the y-intercept is -8.

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15y ago

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