Where an equation is presented in this form then convert it to the standard slope intercept format of y = mx + c. The value of m is the slope. 3x - 7y = 14 7y = 3x - 14 y = 3/7x - 2 The slope is therefore 3/7.
The slope-intercept form of the equation of a line is y = mx + b, where m is the slope and b is the y-intercept. To put 3x - 2y = 16 in slope-intercept form just requires a little rearranging: 3x - 2y = 16 -2y = -3x + 16 (subtract 3x from both sides) y = 3/2x - 8 (divide all terms by -2) Now the equation is in slope-intercept form. The slope m is 3/2; the y-intercept is -8.
-1
3x-6y=12; subtract 12 & add 6y to both sides 3x-12=6y; divide by 6 (1/2)x-2=y; re-write y=(1/2)x-2 slope intercept form
3x + 2y = 8 2y=8-3x y=4-1.5x A quadratic has x^2 This is the equation of a line with negative slope.
5
1
3
-3
It is:- 3x+4y = 8 4y = -3x+8 y = -0.75x+2 So the slope is -0.75 and the y intercept is 2
The slope of the boundary line is 3/2.
3X - 2Y = - 16 - 2Y = - 3X - 16 Y = (3/2)X + 8 ==============slope intercept form
-5
y = 2/3x - 2
y=2/3x-7
-1
The slope is infinite because x = 2/3, a vertical line, for all values of y.