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When the equation of the line is written in the above (slope-intercept) form,
Slope = coefficient of x = 3
y-Intercept = constant term = -2
Where an equation is presented in this form then convert it to the standard slope intercept format of y = mx + c. The value of m is the slope. 3x - 7y = 14 7y = 3x - 14 y = 3/7x - 2 The slope is therefore 3/7.
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The slope-intercept form of the equation of a line is y = mx + b, where m is the slope and b is the y-intercept. To put 3x - 2y = 16 in slope-intercept form just requires a little rearranging: 3x - 2y = 16 -2y = -3x + 16 (subtract 3x from both sides) y = 3/2x - 8 (divide all terms by -2) Now the equation is in slope-intercept form. The slope m is 3/2; the y-intercept is -8.
3x-6y=12; subtract 12 & add 6y to both sides 3x-12=6y; divide by 6 (1/2)x-2=y; re-write y=(1/2)x-2 slope intercept form
3x + 2y = 8 2y=8-3x y=4-1.5x A quadratic has x^2 This is the equation of a line with negative slope.