0.45 repeated = 5/11
METHOD #1
0.45 repeated = 0.45 + 0.0045 + 0.000045 ...
r = 0.01 [common ratio between each term]
n = 0.45 [beginning term]
As |r|<1
0.45 + 0.0045 + 0.000045 ... forms a limiting sum
Limiting sum = S(n) = n / (1 - r)
= 0.45/(1 - 0.01)
= 0.45/0.99
= 45/99
= 5/11
METHOD #2
Let x = 0.45 repeated
100x = 45.45 repeated
100x - x = 45.454545454545... - 0.454545454545...
99x = 45
x = 45/99
x = 5/11
0.454545...
Let P = 0.454545....
Hence
100P = 45.454545...
Subtract
99P = 45. 0 = 45 ( NB THe recurring decimals to infinity subtract to zero.
99P = 45
P = 45/99
Cancel down by '9'
5/11
The answer!!!!
1.'19' repeating '19' as a fraction is 118/99
If all 3 digits are repeating then as a fraction it is 215/999
The fraction for .4 repeating is 2/5.
It is: 82/99 = 0.828282.....repeating
It is: 2/15 as a fraction
0.045 = 45/1000 or 9/200 in fraction
45/100
what is 0.194 as a repeating fraction
0.78 repeating as a fraction = 78/99
0.14 repeating as a fraction = 14/99
If you mean: 0.151515.....repeating then as a fraction it is 5/33
3.1 repeating, as a rational fraction is 28/9.
0.13333333 repeating in fraction = 12/90 or 2/15
3.25 repeating written as a fraction is 322/99
1.'19' repeating '19' as a fraction is 118/99
If all 3 digits are repeating then as a fraction it is 215/999
The fraction of the repeating decimal 0.7... is 7/9