1,005 Is divisible by 5 cause ' it ends w/ 5 and 3 cause' the sum is 6
To find a 4-digit number that is divisible by both 5 and 7, we need to find the least common multiple of 5 and 7, which is 35. The smallest 4-digit number divisible by 35 is 1005 (35 x 29 = 1005). The largest 4-digit number divisible by 35 is 9945 (35 x 284 = 9945). Therefore, the 4-digit numbers divisible by both 5 and 7 range from 1005 to 9945.
1005 m = 3297.244 '
0.0149
1005 ÷ 15 = 67
455.8603kg
1005, 1020, 1035 and so on.
It is: 1005
1000 1005 1010 1015 1020 and so on ...
1005 is one of 1350 possible answers.
A 4-digit number divisible by both 5 and 9 must be divisible by their least common multiple, which is 45. To find a 4-digit number divisible by 45, we need to find a number that ends in 0 and is divisible by 45. The smallest 4-digit number that fits these criteria is 1005 (45 x 22 = 990, and adding 15 gives us 1005).
As written, the question doesn't make sense. There is no number that is divisible by 5 but not by 5. In case you meant but not by 4, try 1005 or 1035.
1005 = MV
1005-739 = 266
If you want a whole number, the answer is 1005, but if you don't mind that's a decimal, you can use 1000.000000005
Well, isn't that a lovely little math problem we have here? Let's see, to find two numbers that multiply together to equal 1005, we can break it down into its factors. After a bit of happy math, we find that 45 times 23 equals 1005. Happy little numbers, just waiting to be discovered!
1005 m = 3297.244 '
1005 = 3 * 5 * 67