log(x) + log(2) = log(2)Subtract log(2) from each side:log(x) = 0x = 100 = 1
You cannot solve log x- 2 unless (i) log x - 2 is equal to some number or (ii) x is equal to some number.
0.00219666107516574806294432462657...
14! = 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 x 10 x 11 x 12 x 13 x 14 = 87178291200
720720 Prime factorised in power format: 2 = 2 3 = 3 4 = 2² 5 = 5 6 = 2 x 3 7 = 7 8 = 2³ 9 = 3² 10 = 2 x 5 11 = 11 12 = 2² x 3 13 = 13 14 = 2 x 7 15 = 3 x 5 16 = 2⁴ lcm = 2⁴ x 3² x 5 x 7 x 11 x 13 = 720720
11
11.2
Prime factorization:14 = 2 x 744 = 2 x 2 x 11 = 22 x 11The LCM of 14 and 44 is 22 x 7 x 11 = 308.308
log(x) + log(2) = log(2)Subtract log(2) from each side:log(x) = 0x = 100 = 1
1 x 14, 2 x 7, 7 x 2, 14 x 11 x 14, 2 x 7.
(2, 11)
log x + 2 = log 9 log x - log 9 = -2 log (x/9) = -2 x/9 = 10^(-2) x/9 = 1/10^2 x/9 = 1/100 x= 9/100 x=.09
log base 2 of [x/(x - 23)]
log x2 = 2 is the same as 2 log x = 2 (from the properties of logarithms), and this is true for x = 10, because log x2 = 2 2 log x = 2 log x = 1 log10 x = 1 x = 101 x = 10 (check)
(-22-x)/(3-14) = 2 + x/11
[log2 (x - 3)](log2 5) = 2log2 10 log2 (x - 3) = 2log2 10/log2 5 log2 (x - 3) = 2(log 10/log 2)/(log5/log 2) log2 (x - 3) = 2(log 10/log 5) log2 (x - 3) = 2(1/log 5) log2 (x - 3) = 2/log 5 x - 3 = 22/log x = 3 + 22/log 5
The least common multiple of the numbers 18, 10 and 14 is 630.