No. Add the digits of the dividend and if that is divisible by 3 then the original number is divisible by 3; if not, its remainder when divided by 3 gives the remainder when the original number is divided by 3: 1 + 2 + 1 = 4 which gives a remainder of 1 when divided by 3, so 121 divided by 3 gives a remainder of 1. (121 = 40 x 3 + 1)
121
It will be 3.
1,11,and 121
15.125
121
No. Add the digits of the dividend and if that is divisible by 3 then the original number is divisible by 3; if not, its remainder when divided by 3 gives the remainder when the original number is divided by 3: 1 + 2 + 1 = 4 which gives a remainder of 1 when divided by 3, so 121 divided by 3 gives a remainder of 1. (121 = 40 x 3 + 1)
121 divided by 3 equals 40 with a remainder of 1.
12.3333
121
121
363 can be divided evenly by: 1, 3, 11, 33, 121, and 363.
It will be 3.
1,11,and 121
15.125
the way you can get 121 you do is 121-8=113 and there is your answer
121