12=n in a d
The sum of the first 12 terms of an arithmetic sequence is: sum = (n/2)(2a + (n - 1)d) = (12/2)(2a + (12 - 1)d) = 6(2a + 11d) = 12a + 66d where a is the first term and d is the common difference.
0.3333
This is an arithmetic sequence which starts at 14, a = 14, and with a common difference of -1, d = -1. We can use the nth term formula an = a + (n - 1)d to get an = 14 + (n - 1)(-1) = 14 - n + 1 = 15 - n.
I'll use these symbols for each coin: P = Penny; D = Dime; N = Nickel 12 P 7 P & 1 N (7 + 5) 2 P & 2 N (2 + 10) 1 D & 2 P (10 + 2)
12=n in a d
N. D. Opara was born on 1985-12-14.
12 disciples of Jesus of Nazareth
denomination
The sum of the first 12 terms of an arithmetic sequence is: sum = (n/2)(2a + (n - 1)d) = (12/2)(2a + (12 - 1)d) = 6(2a + 11d) = 12a + 66d where a is the first term and d is the common difference.
There are 22 ways to make change from a dollar using nickels, dimes, and quarters. 1. 4 q 2. 10 d 3. 20 n 4. 2 q , 5 d 5. 3 q , 2 d , 1 n 6. 1 q , 7 d, 1 n 7. 9 d, 2 n 8. 8 d, 4 n 9. 7 d, 6 n 10. 6 d , 8 n 11. 5 d , 10 n 12. 4 d , 12 n 13. 2 d , 16 n 14. 1 d , 18 n 15. 5 n , 3 q 16. 3 n , 1 q , 6 d 17. 7 n , 1 q , 4 d 18. 9 n , 1 q , 3 d 19. 11 n , 1 q , 2 d 20. 13 n , 1 q , 1 d 21. 14n , 3 d 22. 15n , 1 q
12 vie is a gay p**n site :D and means hairy balls
The nth term of an AP with initial term a (= u{1}) and common difference d is given by: u{n} = a + (n - 1)d In this case: a = 6 d = (12 - 6) = 6 → u{n} = 6 + (n - 1)6 But this can be simplified: u{n} = 6 + (n - 1)6 = 6 + 6n - 6 = 6n
N-Y-P-D- - 1967 The Boy Witness 1-12 was released on: USA: 28 November 1967
N-Y-P-D- - 1967 The Love Hustle 2-12 was released on: USA: 31 December 1968
#include <stdio.h> #include <conio.h> void main() { int n ,i,j,temp,a[12]; //in a[] specify some number . printf("Enter the no of inputs:"); scanf("%d", &n); printf("Enter %d integer numbers :", n); for(i=0;i<n;i++) { scanf("%d",&a[i]); } for (i=0;i<n;i++) for(j=i+1;j<n;j++) { if(a[i]>a[j]) { temp=a[j]; a[j]=a[i]; a[i]=temp; } } printf("THE %d NUMBERS SORTED IN ASCENDING ORDER ARE :\n", n); for(i=0;i<n;i++) { printf("%d ",a[i]); } getch(); }
HERE IS IT!!!!!#include#includevoid main(){int a[12],b[12],c[12],i,j=0,k=0;clrscr();printf("Enter an integer\n");for(i=0;i