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The sum of the first 12 terms of an arithmetic sequence is:

sum = (n/2)(2a + (n - 1)d)

= (12/2)(2a + (12 - 1)d)

= 6(2a + 11d)

= 12a + 66d

where a is the first term and d is the common difference.

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It is 12/2*(2a + 11/d) where a is the first number and d is the common difference of the sequence.

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7y ago
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Q: What is the sum of the first 12 terms of the arithmetic sequence?
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