The sum of the first 12 terms of an arithmetic sequence is:
sum = (n/2)(2a + (n - 1)d)
= (12/2)(2a + (12 - 1)d)
= 6(2a + 11d)
= 12a + 66d
where a is the first term and d is the common difference.
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It is 12/2*(2a + 11/d) where a is the first number and d is the common difference of the sequence.
a1=2 d=3 an=a1+(n-1)d i.e. 2,5,8,11,14,17....
49
To find the sum of the first 48 terms of an arithmetic sequence, we can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum of the first n terms, a1 is the first term, and an is the nth term. In this case, a1 = 2, n = 48, and an = 2 + (48-1)*2 = 96. Plugging these values into the formula, we get: S48 = 48/2 * (2 + 96) = 24 * 98 = 2352. Therefore, the sum of the first 48 terms of the given arithmetic sequence is 2352.
sequence 4 5 6 sum =10 sequecnce 0 5 10 sum=10
An arithmetic sequence is a list of numbers which follow a rule. A series is the sum of a sequence of numbers.