yes it is because 16 is divisible by 2,4,and 8
No.
No.
Not evenly because it will have a remainder of 4
The digital root (sum of digit) must be divisible by 9, and the number formed by the last 4 digits must be divisible by 16. The second requirement ensures that the number is divisible by 16.
Nope. 16 is divisible by 1, 2, 4, 8, 16.
No, it is not divisible by 3. Add all the digits of 21733, we will get 16 & 16 is not divisible by 3.
yes it is because 16 is divisible by 2,4,and 8
One hundred forty-four is divisible by 16. It is equal to 9.
16. ===
No; 1+7+3+5= 16 16 isn't divisible by 3.
No. It doesn't end in a 5 or 0.
No.
No.
No.
No.
No.