To convert base 16 to base 2 DIRECTLY without base 2, consider that each base 16 digit represents four base 2 bits. Just write down the base 2 equivalent for each base 16 digit.0 - 00001 - 00012 - 00103 - 00114 - 01005 - 01016 - 01107 - 01118 - 10009 - 1001A - 1010B - 1011C - 1100D - 1101E - 1110F - 1111Example: 51C35 -> 01011 -> 0001C > 11003 -> 0011So 51C3 -> 0101000111000011(But you should delete the leading 0, hence 101000111000011.)
110010 base 2 has one 2, one 16 and one 32 32 + 16 + 2 = 50 base 10
area of triangle =(1/2)(base)(height) 16=(1/2)(4)h h=8
110110 that's 32+16+0+4+2+0
the binary system is base 2 and the hexadecimal system is base 16
B5 in base 16.
The binary representation of 16 is "10000" in base two.
10011110 base 2 = 9E base 16
16
Both base 16 and base 2 number systems use binary numbers (1 and 0) to write out and define decimal numbers.
10000
59 = 32 + 16 + 8 + 2 +1 = 111011 base 2
To convert base 16 to base 2 DIRECTLY without base 2, consider that each base 16 digit represents four base 2 bits. Just write down the base 2 equivalent for each base 16 digit.0 - 00001 - 00012 - 00103 - 00114 - 01005 - 01016 - 01107 - 01118 - 10009 - 1001A - 1010B - 1011C - 1100D - 1101E - 1110F - 1111Example: 51C35 -> 01011 -> 0001C > 11003 -> 0011So 51C3 -> 0101000111000011(But you should delete the leading 0, hence 101000111000011.)
110010 base 2 has one 2, one 16 and one 32 32 + 16 + 2 = 50 base 10
pythagoreon thereom 34sq - 30sq = 256 sqrt = 16 base 16+16 = 32 half length of base = SQR(34^2 - 30^2) =SQR(1156-900) =SQR(256) =16 base length = 2x 16=32
area of triangle =(1/2)(base)(height) 16=(1/2)(4)h h=8
The math for base 16 is easier and faster than the math for base 2.