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The logarithm base 4 of 16 is asking the question "4 raised to what power equals 16?" In this case, 4 squared is equal to 16, so the answer is 2. Therefore, log base 4 of 16 is equal to 2.

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The answer is 16

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12y ago
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Q: What is log base 4 of 16?
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How do you solve the equation 5.2 log4 2x16?

Due to limitations with browsers mathematical operators (especially + =) get stripped from questions (leaving questions with not enough information to answer them) and it is not entirely clear what the log4 bit means. I guess that the log4 bit is logarithms to base 4 of 2x^16 (which I'll write as log_4(2x^16) for brevity). If this is so, use normal algebraic operations to make log_4(2x^16) the subject of the equation. With logs there are useful rules; given 2 numbers 'a' and 'b': log(ab) = log(a) + log(b) log(a^b) = b × log(a) Which means: log_4(2x^16) = log_4(2) + log_4(x^16) = log_4(2) + 16 × log(x) and the equation can be further rearranged: log_4(2x^16) = <whatever> → log_4(2) + 16 × log(x) = <whatever> → log(x) = (<whatever> - log_4(2)) / 16 Logarithms tell you the power to which the base of the logarithm must be raised to get its argument, for example when using common logs: lg 100 = 2 since 10 must be raised to the power 2 to get 100, ie 10² = 100. (lg is the abbreviation for logs to base 10; ln, or natural logs, is the abbreviation for logs to the base e.) With logs to base 4, it is 4 that is raised to the power of the log to get the original value. eg log_4(16) = 2 since 4^2 = 16. log_4(2) can be worked out: The log to any base of the base is 1 (since any number to the power 1 is itself). Now 2 × 2 = 2² = 4. → log_4(4) = 1 → log_4(2²) = 1 → 2 × log_4(2) = 1 → log_4(2) = ½ → log(x) = (<whatever> - ½) / 16 Back to the rearranged equation; with logs to base 4, if you make both sides the power of 4 you'll get: 4^(log_4(x)) = 4^(<whatever>) → x = 4^(<whatever>) which now solves for x.


Evaluate 81 to the power of log 16 with a base of 9?

It is 256.


How do you simplify log base 3 25 plus log base 3 4 and express using base 10 logarithms?

log325 + log34 = log3(25*4) = log3(100) = log10100/log103 = 2/log103


What is the same thing as log base e?

log base e = ln.


What is twenty five percent of sixteen?

64 Base = Percentage/Rate Base = 16/25% = 16/0.25 = 64 thus; 25% of 64 is equal to 16.