Twice - with 40 remaining.
180 times 3 = 540
Supplementary angles add up to 180° Let the smaller angle be x, then the larger angle is x + 70°, and: x + (x + 70°) = 180° → 2x + 70° = 180° → 2x = 110° → x = 55° → x + 70° = 55° + 70° = 125° Thus the two angles are 55° and 125°. Therefore the angle you want is the larger at 125°.
15 x 12 = 180
20 times 9 is 180.
Twice - with 40 remaining.
30 * 76 = 30 * (70 + 6) = 30*70 + 30 * 6 = 2100 + 180 = 228030 * 76 = 30 * (70 + 6) = 30*70 + 30 * 6 = 2100 + 180 = 228030 * 76 = 30 * (70 + 6) = 30*70 + 30 * 6 = 2100 + 180 = 228030 * 76 = 30 * (70 + 6) = 30*70 + 30 * 6 = 2100 + 180 = 2280
Let the angle be A, then the supplementary angle is (180 - A) and the complementary angle is (90 - A). 180 - A = 70 + 5(90 - A) = 70 + 450 - 5A = 520 - 5A 4A = 520 - 180 = 340 A = 85° Then, 95 = 70 + 5(5) = 70 + 25 = 95
The Least Common Multiple (LCM) of 180 and 70 is 1,260.
This is a subtraction problem. 250 - 70 = 180. This is true because 180 + 70 = 250.
180 600*70% = 420 600-420 = 180
The LCM is 2520.
70 x 30 = 2100 6 x 30 = 180 2100 + 180 = 2280 30 x 76 = 2280
The sum of all three angles is 180 deg so the answer is 180 - (30 + 70) = 80 deg.The sum of all three angles is 180 deg so the answer is 180 - (30 + 70) = 80 deg.The sum of all three angles is 180 deg so the answer is 180 - (30 + 70) = 80 deg.The sum of all three angles is 180 deg so the answer is 180 - (30 + 70) = 80 deg.
(126/180)*100 = 70%
A supplementary angles are 2 angles that equal 180. 70+110=180
0.7 x 180 = 126