0.0678
That all depends upon what the first digit is. For example: First digit is 1. Answer is: 8 First digit is 2. Answer is 16. First digit is 3. Answer is 24.
12.5
The process of multiplication doesn't produce remainders.The process of division does.If you want to divide a 3-digit number by a one-digit numberand get a remainder of 8, try these:107 divided by 9116 divided by 9125 divided by 9134 divided by 9143 divided by 9..Add as many 9s to 107 as you want to, and then divide the result by 9.The remainder will always be 8.
58, 118, 178, ... That is all numbers that are 60n - 2 where n = 1, 2, 3, ... It has a remainder of 3 when divided by 5, means the last digit must be 3 or 8. It also has a remainder of 2 when divided by 4, means that the number must be even, so the last digit must be 8. It also has a remainder of 1 when divided by 3, means it must be 1 more than a multiple of 3 that ends in 7. So it must be 28, 58, 88, 118, ..., (each number 30 more than the last) but 28, 88, ... are divisible by 4, so only 58, 118, ... (each number 60 more than the last) need be considered. It also has a remainder of 4 when divided by 6, means it must be 4 more than a multiple of 6 that ends in 4. So it must be 58, 118, ...
118
0.0678
That all depends upon what the first digit is. For example: First digit is 1. Answer is: 8 First digit is 2. Answer is 16. First digit is 3. Answer is 24.
12.5
8.1304
The process of multiplication doesn't produce remainders.The process of division does.If you want to divide a 3-digit number by a one-digit numberand get a remainder of 8, try these:107 divided by 9116 divided by 9125 divided by 9134 divided by 9143 divided by 9..Add as many 9s to 107 as you want to, and then divide the result by 9.The remainder will always be 8.
2 x 6 + 0 = 12 2 x 1 + 2 = 4 4 is not [divisible by] 8, so 60 is not divisible by 8. (The remainder when 60 is divided by 8 is 4). To test divisibility by 8: Add together the hundreds digit multiplied by 4, the tens digit multiplied by 2 and the units (ones) digit. If this sum is divisible by 8 so is the original number. (Otherwise the remainder of this sum divided by 8 is the remainder when the original number is divided by 8.) If you repeat this sum on the sum until a single digit remains, then if that digit is 8, the original number is divisible by 8 otherwise it gives the remainder when the original number is divided by 8 (except if the single digit is 9, in which case the remainder is 9 - 8 = 1).
It is 7824/10 = 782.4 and so now the digit 8 represents 80
58, 118, 178, ... That is all numbers that are 60n - 2 where n = 1, 2, 3, ... It has a remainder of 3 when divided by 5, means the last digit must be 3 or 8. It also has a remainder of 2 when divided by 4, means that the number must be even, so the last digit must be 8. It also has a remainder of 1 when divided by 3, means it must be 1 more than a multiple of 3 that ends in 7. So it must be 28, 58, 88, 118, ..., (each number 30 more than the last) but 28, 88, ... are divisible by 4, so only 58, 118, ... (each number 60 more than the last) need be considered. It also has a remainder of 4 when divided by 6, means it must be 4 more than a multiple of 6 that ends in 4. So it must be 58, 118, ...
The first 8 digit number is 10,000,000, the last is 99,999,999 which means there are 90,000,000 8 digit numbers
Eight hundredths.
The number 72, when divided by 9, the correct answer is 8. This is not a four digit numeric. To express 72 as a four digit numeric, write 0072. 0072 / 9 = 8.