40 + 2
the partial products for 84 and 78 6000,500,50,and 2 :)
To find the partial products of 452 times 12, you can break it down by multiplying each digit of 12 by the entire number 452. First, multiply 452 by 2 (the ones place), which gives you 904. Then, multiply 452 by 10 (the tens place), resulting in 4520. The partial products are 904 and 4520, which can be added together to get the final product of 5424.
To find the partial products of 30 x 82, you can break down the numbers into simpler components. First, you can express 82 as 80 + 2. Then, calculate the partial products: 30 x 80 = 2400 and 30 x 2 = 60. Finally, add the partial products together: 2400 + 60 = 2460.
2877.5
The partial products for 734X29 are 6,606 and 14,680.
2/7 times 21 = 6
As a product of its prime factors: 2*5*563 = 5630
They are: 30*20, 30*8, 2*20 and 2*8.
To find the partial products of 62 x 45, we can break it down into simpler components. First, we multiply 60 (from 62) by 40 (from 45) to get 2400. Then, we multiply 60 by 5 to get 300, and finally, we multiply 2 (from 62) by 40 to get 80, and 2 by 5 to get 10. Adding these partial products together: 2400 + 300 + 80 + 10 gives us a total of 2790.
42 ÷ 21 = 2
441 x 2 = 882
6/63=3(2)/3(21)=2/21 2/21 times.