1 x 58, 2 x 29, 29 x 2, 58 x 1.
A little bity of algebra 2 X x = 58 Divide both sides by '2' x = 58/2 x = 29 The answer!!!!!
-5 and 2, or -2 and 5 But here's a step by step solution of how to get there: System with two variables: {x+7=y {x²+y²=29 Substitution of 1 into 2: x²+(x+7)²=29 Expansion: x²+x²+14x+49=29 Simplification: 2x²+14x+20=0 Distribution: (2x+10)(x+2)=0 Solve for x: 2x+10=0 or x+2=0 2x=-10 or x=-2 x=-5 or x=-2 Solve for y by plugging in x into equation 1 of the system: -5+7=y or -2+7=y 2=y or 5=y Check your work: -5+7=2 AND -5²+2²=29 ü -2+7=5 AND -2²+5²=29 ü Final answers: (-5, 2) AND (-2,5)
19392 = 2 x 2 x 2 x 2 x 2 x 2 x 3 x 101; 43008 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 3 x 7 HCF = 26 x 3 = 192 19409 / 192 = 101 rem 17 43037 / 192 = 224 rem 29
29 twos in 54 (29 x 2 = 54)
1 x 58, 2 x 29.
2 x 2 x 2 x 2 x 29 x 29 = 13456 2 x 2 x 29 = 116, the square root
2 x 986 4 x 493 17 x 116 29 x 68 34 x 58 2 x 2 x 493 2 x 17 x 58 2 x 29 x 34 4 x 17 x 29 2 x 2 x 17 x 29
348 = 2 x 2 x 3 x 29
The LCM of 29 and 116 is 116. 29 is a prime number, and 116 = 2 x 2 x 29, so you multiply these factors, excluding one occurrence of the common 29, i.e. 29 x 2 x 2, which is 116 which is the LCM (4 x 29, 1 x 116)
The prime factorization of -116 is: -2 x -2 x -29
Primes are 2, 2, 2, 29 Others are combinations of the primes, i.e. 2 x 2 = 4 2 x 2 x 2 = 8 2 x 29 = 58 2 x 2 x 29 = 116
x3 - 6x2 + 4x + 15 = (x - 3)(x - (3/2 + √29/2))(x - (3/2 - √29/2)) ⇒ roots are x = 3, x = 3/2 + √29/2 (≈ 4.19), or x = 3/2 - √29/2 (≈ -1.19)
1 x 58, 2 x 29, 29 x 2, 58 x 1.
The prime factors are: 2 x 29
29 is the prime factor. the entire factors are 2 * 2 * 29 = 116
In the future please be more specific as to what you are asking. Factoring: 2 x 2 x 2 x 29 In other terms: 23 x 29 or 8 x 29